Answer
Find out how many seconds faster has Alexandria's time then Adele's time .
To proof
Let us assume that seconds faster has Alexandria's time then Adele's time be x.
As given in the question
Adele Swam the length of the pool in 32.56 seconds. Alexandria swam the length of the pool in 29.4 seconds.
Than the equation becomes
x = 32.56 - 29.4
x = 3.16 seconds
Therefore the 3.16 seconds faster has Alexandria's time then Adele's time .
Hence proved
Answer: B) 3+y+3
This can be simplified to y+6, but the current un-simplified expression has 3 terms.
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Explanation:
Terms are separated by a plus sign. If you had something like 10x-5y, then you would write that as 10x+(-5y) showing that 10x and -5y are the two terms.
Choices A and C, xy and 6y respectively, have one term each. They are considered monomials. Mono = one, nomial = name.
Choice D is the product of the constant 3 and the binomial y+3. Binomials have two terms.
Only choice B has three terms, though we can simplify it down to two terms. I have a feeling your teacher doesn't want you to simplify it.
15. 5 times 3 is 15.
If you check, 15 divided by 3 is 5(red cars).
Answer:
a rectangle is twice as long as it is wide . if both its dimensions are increased 4 m , its area is increaed by 88 m squared make a sketch and find its original dimensions of the original rectangle
Step-by-step explanation:
Let l = the original length of the original rectangle
Let w = the original width of the original rectangle
From the description of the problem, we can construct the following two equations
l=2*w (Equation #1)
(l+4)*(w+4)=l*w+88 (Equation #2)
Substitute equation #1 into equation #2
(2w+4)*(w+4)=(2w*w)+88
2w^2+4w+8w+16=2w^2+88
collect like terms on the same side of the equation
2w^2+2w^2 +12w+16-88=0
4w^2+12w-72=0
Since 4 is afactor of each term, divide both sides of the equation by 4
w^2+3w-18=0
The quadratic equation can be factored into (w+6)*(w-3)=0
Therefore w=-6 or w=3
w=-6 can be rejected because the length of a rectangle can't be negative so
w=3 and from equation #1 l=2*w=2*3=6
I hope that this helps. The difficult part of the problem probably was to construct equation #1 and to factor the equation after performing all of the arithmetic operations.
