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maw [93]
2 years ago
9

A rectangular pool has length of 6 m and 3 m width. The pool is surrounded by a uniform edge with width x m. Given the area of t

he pool side is 32 m². Form a quadratic function and equation for the situation.​
Mathematics
1 answer:
monitta2 years ago
5 0

Answer:

you can solve this problem with the help of this example :

A rectangular pool 20 meters wide and 60 meters long is surrounded by a walkway of uniform width. If the total area of the walkway is 516 square meters, how wide, in meters, is the walkway?

Sol:

A rectangular pool has length l=60m & breadth b=20m.

It has a surrounding walkway of area =516m

2

.

Area (pool) =60×20=1200m

2

Let us take the width of the walkway =

2

X

.

∴ The length as well as the breadth of the area (pool+walkway) will be increased by X

So the length =l of the area (pool+walkway) =(60+X)m and the breadth =b=(20+X)m

∴ Area (pool+walkway) =l×b=[(60+X)×(20+X)]m

2

.

∴ Area (walkway) = Area (pool+walkway) - Area (pool)

=(60+X)×(20+X)−1200=516m

2

....(given)

⇒X

2

+80X−516=0

⇒X=−86 or X=6.

We reject the negative value as X is a length.

So X=6m.

Ans- The width of the walkway =

2

X

=3m.

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Step-by-step explanation:

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Which equation is true when the value of x is -12
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Answer:

Which equation is true when the value of x is -12    HERE YOU GO!!

Step-by-step explanation:

tricky ... let's see ...

I notice that if we subtract xy from both sides we get

7x + xy - xy = xy - xy + 21

then

7x = 21

and

x = 21/7 = 3

so there is only one value of x that satisfies the equation

x = 3

Going back to the original equation we see that any value of y will satisfy the original equation

we can see this by rearranging things:

7x + xy - xy = 21

here, I have performed the subtraction of xy on the right side as above, but have left the left side undone

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Note that the above can also be written as

7x + (x - x)y = 21

or

7x + 0y =21

now, since anything times zero equals zero,

y may be any number.

Let's summarize:

1) x = 3

2) y = anything

looking back at the original question;

1) the equation is true for all ordered pairs

FALSE (only one x works, not all x)

2) there are no x and y pairs for which the equation is true.

FALSE (x=3, y=anything) makes it true, i.e. (3,1)  

3) For each value of x, there is one and only one value of y that makes the equation true,

FALSE for each value of x, for the one value of x, x=3, y can be any number, which is an infinite number, not one

4) for each value of y, there is one and only on value of x that makes the equation true.

TRUE!! for all the infinite values of y you may pick, there is one and only one x you may pick, x = 3

ANSWER: STATEMENT 4 is CORRECT (TRUE)

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3 years ago
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Flura [38]

Answer

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Step-by-step explanation:

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