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maw [93]
2 years ago
9

A rectangular pool has length of 6 m and 3 m width. The pool is surrounded by a uniform edge with width x m. Given the area of t

he pool side is 32 m². Form a quadratic function and equation for the situation.​
Mathematics
1 answer:
monitta2 years ago
5 0

Answer:

you can solve this problem with the help of this example :

A rectangular pool 20 meters wide and 60 meters long is surrounded by a walkway of uniform width. If the total area of the walkway is 516 square meters, how wide, in meters, is the walkway?

Sol:

A rectangular pool has length l=60m & breadth b=20m.

It has a surrounding walkway of area =516m

2

.

Area (pool) =60×20=1200m

2

Let us take the width of the walkway =

2

X

.

∴ The length as well as the breadth of the area (pool+walkway) will be increased by X

So the length =l of the area (pool+walkway) =(60+X)m and the breadth =b=(20+X)m

∴ Area (pool+walkway) =l×b=[(60+X)×(20+X)]m

2

.

∴ Area (walkway) = Area (pool+walkway) - Area (pool)

=(60+X)×(20+X)−1200=516m

2

....(given)

⇒X

2

+80X−516=0

⇒X=−86 or X=6.

We reject the negative value as X is a length.

So X=6m.

Ans- The width of the walkway =

2

X

=3m.

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Chris and Becky are comparing mortgages. The mortgage is for $183,500. If they choose 30 years at 5%, their monthly payment will
Anestetic [448]

Answer:

Total payback for Loan type 1 = $354,625.20

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Explanation

Total payback of a loan consists of the summation of the amount of mortgage to be paid and total interest to be paid after the given number of years.

Total payback of a loan can also be calculated by multiplying your monthly payment of the loan by the total number of months given for payment.

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b. For Loan type 2

In the question we have been given or monthly payment = $1160.91

The formula for Total payback for Loan type 1 = Monthly payment × number of months

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Step-by-step explanation:

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3 years ago
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A = 1/2(8.5+ 15.7) * 7.5

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2 years ago
Right triangles abc and dbc with right angle c are given below. If cos(a)=15,ab=12 and cd=2, find the length of bd.
dmitriy555 [2]

see the attached figure to better understand the problem

we have that

cos(A)=\frac{1}{5} \\ AB=12\ units\\ CD=2\ units

Step 1

<u>Find the value of AC</u>

we know that

in the right triangle ABC

cos (A)=(AC/AB)\\AC=AB*cos(A)

substitute the values in the formula

AC=12*(1/5)\\ AC=2.4\ units

Step 2

<u>Find the value of BC</u>

we know that

in the right triangle ABC

Applying the Pythagorean Theorem

AB^{2} =AC^{2}+BC^{2}\\ BC^{2}=AB^{2} -AC^{2}

substitute the values

BC^{2}=12^{2} -2.4^{2}\\BC^{2}= 138.24\\ BC=11.76\ units

Step 3  

<u>Find the value of BD</u>

we know that

in the right triangle BCD

Applying the Pythagorean Theorem

BD^{2} =DC^{2}+BC^{2}

substitute the values  

BD^{2} =2^{2}+11.76^{2}

BD=11.93\ units

therefore

<u>the answer is</u>

the length of BD is 11.93 units

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