Answer:
true
Step-by-step explanation:
it just is
I believe the answer is 9x ( 2 + 7) = +9 x 2) + (9 x 7)
Answer/Step-by-step explanation:
Problem 1:
Reference angle = 36°
Opposite = x
Adjacent = 7
Thus, apply trigonometric ratio as follows:
tan 36 = x/7
Multiply both sides by 7
7 × tan 36 = x
x = 5.09 (nearest hundredth)
Problem 2:
Reference angle = 63°
Opposite = 12
Hypotenuse = x
Thus, apply trigonometric ratio as follows:
Sin 63 = 12/x
Make x the subject of the formula
x = 12/sin 63
x = 13.47 (nearest hundredth)
Answer:
The probability that the sample mean would differ from the population mean by greater than 0.8 kg is P=0.3843.
Step-by-step explanation:
We have a population with mean 60 kg and a variance of 100 kg.
We take a sample of n=118 individuals and we want to calculate the probability that the sample mean will differ more than 0.8 from the population mean.
This can be calculated using the properties of the sampling distribution, and calculating the z-score taking into account the sample size.
The sampling distribution mean is equal to the population mean.
![\mu_s=\mu=60](https://tex.z-dn.net/?f=%5Cmu_s%3D%5Cmu%3D60)
The standard deviation of the sampling distribution is equal to:
![\sigma_s=\sigma/\sqrt{n}=\sqrt{100}/\sqrt{118}=10/10.86=0.92](https://tex.z-dn.net/?f=%5Csigma_s%3D%5Csigma%2F%5Csqrt%7Bn%7D%3D%5Csqrt%7B100%7D%2F%5Csqrt%7B118%7D%3D10%2F10.86%3D0.92)
We have to calculate the probability P(|Xs|>0.8). The z-scores for this can be calculated as:
![z=(X-\mu_s)/\sigma_s=\pm0.8/0.92=\pm0.87](https://tex.z-dn.net/?f=z%3D%28X-%5Cmu_s%29%2F%5Csigma_s%3D%5Cpm0.8%2F0.92%3D%5Cpm0.87)
Then, we have:
![P(|X_s|>0.8)=P(|z|>0.87)=2*(P(z>0.87)=2*0.19215=0.3843](https://tex.z-dn.net/?f=P%28%7CX_s%7C%3E0.8%29%3DP%28%7Cz%7C%3E0.87%29%3D2%2A%28P%28z%3E0.87%29%3D2%2A0.19215%3D0.3843)