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3 years ago

Determine the probability of having 2 girls and 3 boys in a 5-child family assuming boys and girls are equally likely.

Mathematics

1 answer:

Andrew [12]3 years ago

5 0

The correct answer is 5/16.

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QUESTION 3 [10 MARKS] A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the nu

Harman [31]

Answer:

(a)Revenue function, $R(x)=580x-x^2$

Marginal Revenue function, R'(x)=580-2x

(b)Fixed cost =900 .

Marginal Cost Function=300+50x

(c)Profit, $P(x)=-35x^2+280x-900$

(d)x=4

Step-by-step explanation:

Part A

Price Function $= 580 - 10x$

The revenue function

$R(x)=x\cdot (580-10x)\\R(x)=580x-x^2$

The marginal revenue function

$\dfrac{dR}{dx}= \dfrac{d}{dx}(R(x))=\dfrac{d}{dx}(580x-x^2)=580-2x\\R'(x)=580-2x$

Part B

(Fixed Cost)

The total cost function of the company is given by $c=(30+5x)^2$

We expand the expression

$(30+5x)^2=(30+5x)(30+5x)=900+300x+25x^2$

Therefore, the fixed cost is 900 .

Marginal Cost Function

If $c=900+300x+25x^2$

Marginal Cost Function, $\frac{dc}{dx}= (900+300x+25x^2)'=300+50x$

Part C

Profit Function

Profit=Revenue -Total cost

$580x-10x^2-(900+300x+25x^2)\\580x-10x^2-900-300x-25x^2\\$Profit,P(x)=-35x^2+280x-900$

Part D

To maximize profit, we find the derivative of the profit function, equate it to zero and solve for x.

$P(x)=-35x^2+280x-900\\P'(x)=-70x+280\\-70x+280=0\\-70x=-280\\$Divide both sides by -70\\x=4$

The number of cakes that maximizes profit is 4.

6 0

3 years ago

Pls help I need to find x

Andrews [41]

Answer:

so what i have to do

Step-by-step explanation:

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3 years ago

Write an expression y+3y-2y=

nasty-shy [4]

Answer:

3y=2y

Step-by-step explanation:

Im not sure if this is the answer your looking for but I hope this helped. I tried tho lol :)

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5. This diagram of a baseball field is composed of a square, a semicircle, and a quarter

mart [117]

Answer:this one is hard

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3 years ago

From a group of 6 candidates, a committee of 2 people is selected. In how many different ways can the committee be selected? I k

kolezko [41]

This is a combination problem.

6 nCr 2

$\frac{6!}{2! * (6-2)!} = \frac{720}{48}=15$

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