From a group of 6 candidates, a committee of 2 people is selected. In how many different ways can the committee be selected? I k

Question

3 years ago

13

now the answer is 15 ways , but how do you do it ? 30 points

2 answers:

kolezko [41] · Answer 1 · 2022-03-10T05:18:14+03:00

7 0

This is a combination problem.

6 nCr 2

$\frac{6!}{2! * (6-2)!} = \frac{720}{48}=15$ <span><span>

</span></span>

Artemon [7] · Answer 2 · 2022-03-10T07:11:37+03:00

Answer:

15

Step-by-step explanation:

Here we have to use the combination formula.

nCr = n! / r! (n - r)!

Given: n = 6 and r = 2

Plugging in the given values, we get

6C2 = 6! / 2!(6 - 2)!

= 6! / 2! 4!

6! = 1*2*3*4*5*6 = 720

4! = 1*2*3*4 = 24

2! = 1*2 = 2

6C2 = 720 / 2*24

= 720/48

= 15

We can select in 15 different ways.

Hope this will helpful.

Thank you.