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3 years ago

14

Mathematics

1 answer:

Minchanka [31]3 years ago

6 0

Answer:

B. y = - $\frac{1}{5}$ x - 4

Step-by-step explanation:

The line has a y-intercept of -4, and if one finds the slope through the equation of $\frac{y1-y2}{x1-x2}$ , the answer would be - $\frac{1}{5}$ .

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The figure is made by attaching semicircles to each side of an 11-ft-by-11-ft

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by how much degrees should the heat be reduced in the last 5 minutes of banking

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3 years ago

ANSWER PLEASE 40 POINTS!

tangare [24]

Answer: |10 - (-8)|

The absolute value is 18

Step-by-step explanation:

The distance between two numbers is a subtraction equation.

10 - (-8) Subtracting a negative is like adding a positive

10 + 8 = 18

If you look at it as the first negative sign means -1 multiplied by the next negative number, "Remember that a negative times a negative is a positive!"

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3 years ago

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What is the value of a in this diagram

Delicious77 [7]

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3 years ago

Find the components of the vertical force Bold Upper FFequals=left angle 0 comma negative 10 right angle0,−10 in the directions

quester [9]

Solution :

Let $v_0$ be the unit vector in the direction parallel to the plane and let $F_1$ be the component of F in the direction of $v_0$ and $F_2$ be the component normal to $v_0$ .

Since, $|v_0| = 1,$

$(v_0)_x=\cos 60^\circ= \frac{1}{2}$

$(v_0)_y=\sin 60^\circ= \frac{\sqrt 3}{2}$

Therefore, $v_0 = \left$

From figure,

$|F_1|= |F| \cos 30^\circ = 10 \times \frac{\sqrt 3}{2} = 5 \sqrt3$

We know that the direction of $F_1$ is opposite of the direction of $v_0$ , so we have

$F_1 = -5\sqrt3 v_0$

$=-5\sqrt3 \left$

$= \left$

The unit vector in the direction normal to the plane, $v_1$ has components :

$(v_1)_x= \cos 30^\circ = \frac{\sqrt3}{2}$

$(v_1)_y= -\sin 30^\circ =- \frac{1}{2}$

Therefore, $v_1=\left< \frac{\sqrt3}{2}, -\frac{1}{2} \right>$

From figure,

$|F_2 | = |F| \sin 30^\circ = 10 \times \frac{1}{2} = 5$

∴ $F_2 = 5v_1 = 5 \left< \frac{\sqrt3}{2}, - \frac{1}{2} \right>$

$=\left$

Therefore,

$F_1+F_2 = \left< -\frac{5\sqrt3}{2}, -\frac{15}{2} \right> + \left< \frac{5 \sqrt3}{2}, -\frac{5}{2} \right>$

$= = F$

3 0

2 years ago

4-Fui al supermercado y había un descuento del 15% en el total de la compra, si pagaba en efectivo. Gasté $ 2.400. ¿Qué cantidad

Grace [21]

Answer:

$2.040

Step-by-step explanation:

Para calcular la cantidad que fue abonada en realidad, debes encontrar el valor del descuento calculando el 15% del valor total de la compra y este resultado se debe restar del total:

$2.400*15%= $360

$2.400-$360= $2.040

De acuerdo a esto, la cantidad abonada en realidad es: $2.040.

6 0

3 years ago