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a_sh-v [17]
3 years ago
5

Substance

Chemistry
1 answer:
Grace [21]3 years ago
4 0

Answer:what are u asking to do?

Explanation:

You might be interested in
"How many formula units are there in sample of copper(II) sulfate that has
babymother [125]

Answer: 1.23\times 10^{23} formula units

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{32.5g}{160g/mol}=0.203moles

1 mole of CuSO_4 contains 6.023\times 10^{23} of formula units

Thus 0.203 mole of CuSO_4 contains =\frac{6.023\times 10^{23}}{1}\times 0.203=1.23\times 10^{23} of formula units

8 0
4 years ago
Science.... <br> homework!
Leokris [45]
The answer to this question is 2 and 3
5 0
4 years ago
Plz help me i swear will mark you brainiest :(
vladimir1956 [14]

Answer:

C. the relative molecular mass of the compound

Explanation:

Like molecular formulas, empirical formulas are not unique and can describe a number of different chemical structures or isomers. <u>To determine an empirical formula, the relative molecular mass of the composition of its elements</u> can be used to mathematically determine their ratio.

7 0
3 years ago
In 1906, a 600 g diamond was found at the Premier Mine in South Africa- the world's largest uncut diamond. Suppose the diamond's
lys-0071 [83]

Answer:

852000 J

Explanation:

The following data were obtained from the question:

Mass (M) = 600 g

Change in temperature (ΔT) = 2 °C

Specific heat capacity (C) = 710 J/g℃

Heat transfered (Q) =?

Thus, we can obtain the the heat transfered to the diamond by using the following formula:

Q = MCΔT

Q = 600 × 710 × 2

Q = 852000 J

Therefore, the energy transfered to the diamond by heat is 852000 J

5 0
3 years ago
Calcium nitrate reacts with sodium phosphate to form sodium nitrate and calcium phosphate. Given 96.1 grams of calcium nitrate w
Bingel [31]
Equation is:

Ca(NO3)2 + Na3PO4 —> NaNO3 + Ca3(PO4)2

Balance it out

3Ca(NO3)2 + 2Na3PO4 —> 6NaNO3 + Ca3(PO4)2

You have 96.1g of Calcium Nitrate

Moles = Mass/Molar Mass

Molar mass of Calcium Nitrate is 164.088 g/mol

96.1g / 164.088 g/mol =0.586 moles

Mole ratio is 3:1

Therefore 0.586/3 moles of calcium phosphate

Moles x molar mass = mass

0.586/3 x 310.18 g/mol = 60.6~g roughly as theoretical yield
5 0
4 years ago
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