Question

How much so you can be dissolved and 50 mL of water at 30 Celsius see chart:)

Answer 1

Answer:

The correct answer is - 100 grams.

Explanation:

The solubility graph is a very useful tool because it tells you the amount of solute that can be dissolved per  100 mL  of water in order to have a saturated solution of potassium nitrate at a given temperature.

In order to find the solubility of the salt at  30 ∘ C , start from the  30 ∘ C

mark on the graph and move up until you intersect the curve. At the point of intersection, move left until you intersect the  y  axis and read off the value that you land on which is 200. However, it is for 100 ml so half the value you read:

200/2 = 100 gram .

So, solubility  ≈  100 g / 50 mL water

So, a saturated solution of solute will hold about  100 g  of dissolved solute, that is of dissociated solute, per 50 mL  of water at  30 ∘ C .