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3 years ago

IF ANSWERED CORRECTLY, I WILL GIVE BRAINLYEST

Mathematics

1 answer:

Triss [41]3 years ago

4 0

Answer:

La tercera

-1 2/9

Step-by-step explanation:

Simplify

(−3 2 /3 )( 4 /12 )

(Decimal: -1.222222)

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Express 3/5 as a decimal

lana66690 [7]

Answer:0.60

Step-by-step explanation:

Multiply the denominator (5) and the numerator (3) by 20. Both sides multiplied equals 60 as the numerator and 100 as the denominator. After the conversions to a decimal, your answer should be 0.60 since 60/100=0.60.

4 0

3 years ago

What is 78 in scientific notation

4vir4ik [10]

Well first you take 78 and turn it to 7.8
then multiply by 10000
therefore 7.8*10000= ?

3 0

3 years ago

Solve using elimination. 8x − 7y = –5 –x + 4y = –15

xz_007 [3.2K]

Steps
8x−7y=−5
Add 7y to both sides
8x−7y+7y=−5+7y
Simplify
8x=−5+7y
Divide both sides by 8
8x
8 =−
5
8 +
7y
8
Simplify
x=
−5+7y
8

7 0

3 years ago

Read 2 more answers

Tanya opened a savings account with a deposit of 550.she deposited 450 in the first week and withdrew $120in the second week of

Afina-wow [57]

Just do this 550+450=1000-120=880=750=1630 Now I assume that what you meant to say was what percent of the new balance was the last deposit made. So thats what Im going to be answering off of. We would need to take 1630-750=880 then 880/1630=.54 (rounded to the nearest hundredth) then we need to subtract 54 from one hundread because .54 is how much that the account overgoes the latest deposit making are final answer. That the last deposit that she mad accounted for 46% of the entire account. Enjoy!=)

8 0

3 years ago

A player of a video game is confronted with a series of four opponents and an 80% probability of defeating each opponent. Assume

mixer [17]

Answer:

(a) 0.4096

(b) 0.64

Step-by-step explanation:

The probability that the player wins is,

$P(W)=0.80$

Then the probability that the player losses is,

$P(L)=1-P(W)=1-0.80=0.20$

The player is playing the video game with 4 different opponents.

It is provided that when the player is defeated by an opponent the game ends.

All the possible ways the player can win is: {L, WL, WWL, WWWL and WWWW)

(a)

The results from all the 4 opponents are independent, i.e. the result of a game played with one opponent is unaffected by the result of the game played with another opponent.

The probability that the player defeats all four opponents in a game is,

P (Player defeats all 4 opponents) = $P(W)\times P(W)\times P(W)\times P(W)=[P(W)]^{4} =(0.80)^{4}=0.4096$

Thus, the probability that the player defeats all four opponents in a game is 0.4096.

(b)

The probability that the player defeats at least two opponents in a game is,

P (Player defeats at least 2) = 1 - P (Player losses the 1st game) - P (Player losses the 2nd game) = $1-P(L)-P(WL)$

$=1-(0.20)-(0.80\times0.20)\\=1-0.20-0.16\\=0.64$

Thus, the probability that the player defeats at least two opponents in a game is 0.64.

(c)

Let X = number of times the player defeats all 4 opponents.

The probability that the player defeats all four opponents in a game is,

P(WWWW) = 0.4096.

Then the random variable $X\sim Bin(n=3, p=0.4096)$

The probability distribution of binomial is:

$P(X=x)={n\choose x}p^{x} (1-p)^{n-x}$

The probability that the player defeats all the 4 opponents at least once is,

P (X ≥ 1) = 1 - P (X < 1)

= 1 - P (X = 0)

$=1-[{3\choose 0}(0.4096)^{0} (1-0.4096)^{3-0}]\\=1-[1\times1\times (0.5904)^{3}\\=1-0.2058\\=0.7942$

Thus, the probability that the player defeats all the 4 opponents at least once is 0.7942.

3 0

3 years ago