All categories

3 years ago

Help quickly as possible thank you :)

Mathematics

2 answers:

STALIN [3.7K]3 years ago

5 0

Answer:

look at the picture, answer is there

Bas_tet [7]3 years ago

5 0

9514 1404 393

Answer:

about 100 years

Step-by-step explanation:

2020 -1920 = 100

Outdoor lights were made safe about 100 years ago. (using information given in the problem statement)

_____

<em>Additional comment</em>

2020 -1930 = 90. So, the actual length of time is <em>between 90 and 100 years</em>.

Using additional research, we find mercury vapor lights were made to have a practical color in about 1929, so 91 years ago. They were invented somewhat before the 1920's but had a greenish color. Fluorescent phosphor coating was added in 1929 to make them produce a whiter light.

You might be interested in

14x+10y=72 14x+4y=96 Solve the following system of equations using any method

Anarel [89]

  14x + 10y = 72
  14x +   4y = 96
  6y = -24
6 6
  y = -4
  14x + 10y = 72
14x + 10(-4) = 72
14x - 40 = 72
+ 40 + 40
  14x = 112
14 14
x = 8
  (x, y) = (8, -4)

5 0

3 years ago

8 times the difference of u and 10

koban [17]

Answer: 8(u - 10)

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

a park is 9/10 mile long and 4/5 mile wide. What is the area of the park? ENTER ANSWER AS A FRACTION FOR EXAMPLE: 4/10.

ASHA 777 [7]

The park formed like a rectangle so :

Area = length × width

Area = ( 9/10 ) × ( 4/5 )

Area = 9 × 4 / 10 × 5

Area = 9 × 2 × 2 / 5 × 5 × 2

Area = 18 / 25

3 0

3 years ago

Solve the system of equations algebraically.

ryzh [129]

Answer:

Step-by-step explanation:

y=3x+24

y-3x=24

y-x= 24/3= 8

y-x = 8

6x +6y= -24

6x+y= -24/6= -4

6x+y= -4

x+y= -4/6= -2/3

x+y= -2/3

8 0

1 year ago

Read 2 more answers

The length of a rectangle is the sum of the width and 4. The area of the rectangle is 32

Sauron [17]

Answer:

The width of rectangle w = 4 units

Step-by-step explanation:

We are given:

Width of rectangle = w

Length of rectangle = w+ 4

Area of rectangle = 32 units

We need to find width of the rectangle

The formula used is: $Area\:of\:rectangle=Length\times Width$

Putting values and finding width of rectangle

$Area\:of\:rectangle=Length\times Width\\32=(w+4)\times w\\32=w^2+4w\\w^2+4w-32=0$

We need to solve this quadratic equation to find width (w)

We will use factorisation and break the middle term.

$w^2+4w-32=0\\w^2+8w-4w-32=0\\w(w+8)-4(w+8)=0\\(w-4)(w+8)=0\\w-4=0\:or\:w+8=0\\w=4\:or\:w=-8$

Since width of rectangle can't be negative, so rejecting w=-8

Therefore, the width of rectangle w = 4 units

4 0

3 years ago

Help quickly as possible thank you :) ​

Help quickly as possible thank you :)