The equation in standard form that passes through (0, -3) and (7, 0) is 3x – 7y = 21
<u>Solution:</u>
Given, two points are (0, -3) and (7, 0)
We have to find that a line that passes through the given two points in standard form.
First let us find the slope of the line that passes through given two points.
The slope of the line "m" is given as:
Now, let us find the line equation using point slope form:
7(y – 0) = 3(x – 7)
7y = 3x – 21
3x – 7y = 21
Hence, the line equation in standard form is 3x – 7y = 21.
D) because “y is” means “y equals” leaving only 2 choices, and it said “6 less than the independent variable, 6. (Y=6-x)
Y - y1 = m(x - x1)
slope(m) = -1/2
(-4,-2)...x1 = -4 and y1 = -2
now we sub
y - (-2) = -1/2(x - (-4) =
y + 2 = -1/2(x + 4) <=====
1)V=Ixwxh
=5 cm x 3 cm x 2 cm
=30 cm³
2)V=bxh
=(10m x 6m) x 4m
= 60 m² x4 m
3)V=Ixwxh
=3 cm x 3 cm x 3 cm =27 cm³
=240 m³
Jan. profit..... 5625.14
feb..loss... - 4250.35
march..profit...1475.55
add the profits and subtract the losses...if the result is positive, then the company made a profit....if the result is negative, then the company had a loss.
(5625.14 + 1475.55) - 4250.35 = 7100.69 - 4250.35 = 2850.34.....as u can see, the result ended in a positive number....so, in the 3 month period, the company made a profit of $ 2850.34 <==
