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iragen [17]
3 years ago
13

What is the volume of a hemisphere with a diameter of 61.5cm?

Mathematics
1 answer:
melamori03 [73]3 years ago
4 0

Answer:

60897cm³ (5sf)

Step-by-step explanation:

Radius = 61.5 ÷ 2 = 30.75cm

Volume of sphere = 4πr³/3

Hemisphere's volume = (4π(30.75)³ ÷ 3) ÷ 2 = 60897cm³ (5sf)

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A plane flying over the ocean is on course to land on an aircraft carrier. The diagonal distance between the plane and the aircr
fomenos

Answer:

the plane's current height above the ocean is 3.42 miles

Step-by-step explanation:

Given that the diagonal distance between the plane and the aircraft carrier is 10 miles.

What we need to find is the vertical distance between the plane and the aircraft carrier which is the plane's current height above the ocean. This can be gotten using sine rule.  

For sine rule, you need a side and its opposite angle. For this question the triangle formed is a right angle triangle with diagonal distance, vertical distance and horizontal distance.

let a = diagonal distance = 10 miles

let the opposite angle to the diagonal distance be A = 90° (right angle)

let the vertical distance = b

let the opposite angle to the vertical distance be B = 20°

Sine rule states that    \frac{a}{sin(A)}  =  \frac{b}{sin(B)}

∴   \frac{10}{sin(90)}  =  \frac{b}{sin(20)}

b  =  sin(20)\frac{10}{sin(90)}

b  =  0.342*\frac{10}{1}

⇒ b = 3.42 miles

Therefore the plane's current height above the ocean is 3.42 miles

4 0
3 years ago
In 2000, the circulation of a local newspaper was 3,250. In 2001, its circulation was 3,640. In 2002, the circulation was 4,100.
vodka [1.7K]

Percent increase from 2000 to 2001 is 12% and from 2001 to 2002 is 12.6%. Thus period of 2001 to 2002 has higher increase percentage.

<u>Solution:</u>

Given that,

Total circulation of local newspaper in 2000 = 3250

Total circulation of local newspaper in 2001 = 3640

Total circulation of local newspaper in 2002 = 4100

<em><u>Finding percent of increase in the newspaper’s circulation from 2000 to 2001:</u></em>

\text { Percent increase from } 2000 \text { to } 2001=\frac{\text { change in circulation from 2001 - 2000 }}{\text { circulation in } 2000} \times 100

\begin{array}{l}{=\frac{3640-3250}{3250} \times 100} \\\\ {=\frac{390}{3250} \times 100=12 \%}\end{array}

<em><u>Finding percent of increase in the newspaper’s circulation from 2001 to 2002:</u></em>

\begin{array}{l}{\text { Percent increase from } 2001 \text { to } 2002=\frac{\text { change in circulation }}{\text {circulation in } 2001} \times 100} \\\\ {=\frac{4100-3640}{3640} \times 100} \\\\ {=\frac{460}{3640} \times 100=12.6 \%}\end{array}

As we can see 12% < 12.6%

So period of 2001 to 2002 has higher increase percentage.

7 0
3 years ago
Eric works in landscaping. He charges a fee of $25 plus $15 per hour. What is the least number of hours he must work in order to
nlexa [21]

Answer:

5 hours

Step-by-step explanation:

you would so 100 minus 25 (25 is just one charge fee) which is 75 then divide 75 into 15 which is the hourly pay, and get 5 which is the hours he must work

3 0
3 years ago
A factory makes 12 bikes in 3 hours. If it keeps making bikes at the same rate, how many bikes will it have made in 8 hours? (HI
Vilka [71]

Answer:32

Step-by-step explanation: 4 bikes every hour so multiply 4 times 8 which is 32

4 0
3 years ago
What’s 40 41 42 43 44 45 46 47 48 49 50 IQR pls fast!!!!!
aliina [53]

Answer:

IQR = 6

Step-by-step explanation:

Given:

The given set of data is:

40 41 42 43 44 45 46 47 48 49 50

Number of terms, n=11

Therefore, the median is given as (\frac{n+1}{2})^{th} term which is the sixth term. Median = 45

(40 41 42 43 44) <u>45</u> (46 47 48 49 50 )

Now, we find the median of the lower half (Q_1) and upper half (Q_3)of the data that are before and after the median.

The lower half of the data has the values 40 41 <u>42</u> 43 44.

Number of terms are 5. So, median is the third term which is, Q_1=42

The upper half of the data has the values 46 47 <u>48</u> 49 50.

Number of terms are 5. So, median is the third term which is, Q_3=48

Now, IQR is given as the difference of upper half median and lower half median.

IQR=Q_3-Q_1\\IQR=48-42=6

4 0
4 years ago
Read 2 more answers
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