Well knowing these are both obtuse angles of the same shape and size we can begin. were looking to show AC is equal to DF we start by connecting A to C. A goes to C and makes this half an Oval shape along the bottom line now try connecting A to B and C to B AB and CB are not the same as AC and since these angles are the same shape and size we know DF should do the same so now we connect D to E and F to E similar to AC they do not match nor do they match AC itself leaving us to compare D to F after we do this we see that it creates the same sized half an oval as AC showing us that they are equal. :)
Answer:
A. v(t) = sin (2πft + π/2) = A cos (2πft)
Step-by-step explanation:
According to trigonometry friction, the following relationship are true;
Sin(A+B) = sinAcosB + cosAsinB
We will be using this relationship to check which option is true.
Wave equation is represented as shown;
y(t) = Asin(2πft±theta)
For positive displacement,
y(t) = Asin(2πft+theta)
If theta = π/2
y(t) = Asin(2πft+π/2)
y(t) = A[ sin 2πftcosπ/2 + cos2πft sin π/2]
Since sinπ/2 = 1 and cos (π/2) = 0
y(t) = A[ sin 2πft (0)+ cos2πft (1)]
y(t) = A[0+ cos2πft]
y(t) = Acos2πft
Hence the expression that is true is expressed as;
v(t) = Asin(2πft+π/2) = Acos2πft
I think you might need to be more specific..
Answer:
Step-by-step explanation:
Answer:
Step 1: Remove parentheses by multiplying factors.
= (x * x) + (1 * x) + (2 * x) + (2 * 1)
Step 2: Combine like terms by adding coefficients.
(x * x) = x2
(1 * x) = 1x
(2* x) = 2x
Step 3: Combine the constants.
(2 * 1) = 2
Step 4: Therefore, Simplifying Algebraic Expression is solved as
= x2 + 3x + 2.
