Answer:
Part 1) The measure of arc EHL is 
Part 2) The measure of angle LVE is 
Step-by-step explanation:
step 1
Let
x-----> the measure of arc EHL
y----> the measure of arc EVL
we know that
The measurement of the outer angle is the semi-difference of the arcs it encompasses.
so

we have

substitute

------> equation A
Remember that
-----> equation B ( complete circle)
substitute equation A in equation B and solve for x



Find the value of y


therefore
The measure of arc EHL is 
The measure of arc EVL is 
step 2
Find the measure of angle LVE
we know that
The inscribed angle measures half that of the arc comprising
Let
x-----> the measure of arc EHL

we have

substitute

I think the expression is
3t(5.4n + 1.8 )
Triangles
ABC - AB=2.5, BC=1.5, CA=2 (5: 3: 4)
ADC - AC=2, CD= 1.2, DA= 1.6
BCD - BC=1.5, BD = 0.9, DB = 1.2
Area
ABC = 1/2 *AC * CB = 1/2 *2 * 1.5 = 1.5 m^2
ADC = 1/2 *AD * DC = 1/2 * 1.6 * 1.2 = 0.96 m^2
BCD = 1/2 *BD * DC = 1/2 * 0.9 * 1.2 = 0.54 m^2
Answer:
It would be A. x < 6
Step-by-step explanation:
The number line shows it is less than six with a closed circle and the arrow pointing towards the left of it