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Paladinen [302]
3 years ago
7

The measure of two opposite interior angles of a triangle are and. The exterior angle of the0x−14x+4triangle measures. Solve for

the measure of the3x4+5exterior angle.
Mathematics
1 answer:
11111nata11111 [884]3 years ago
6 0

Answer:

60 degrees

Step-by-step explanation:

Restructured question:

The measure of two opposite interior angles of a triangle are x−14 and x+4. The exterior angle of the triangle measures 3x-45 . Solve for the measure of the exterior angle.

First you must know that the sum of interior angle of a triangle is equal to the exterior angle

Interior angles = x−14 and x+4

Sum of interior angles = x-14 + x + 4

Sum of interior angles = 2x - 10

Exterior angle = 3x - 45

Equating both:

2x - 10 = 3x - 45

Collect like terms;

2x - 3x = -45 + 10

-x = -35

x = 35

Get the exterior angle:

Exterior angle =   3x - 45

Exterior angle = 3(35) - 45

Exterior angle = 105 - 45

Exterior angle = 60

Hence the measure of the exterior angle is 60 degrees

<em>Note that the functions of the interior and exterior angles are assumed. Same calculation can be employed for any function given</em>

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Change the subject of the formula L = v 4kt - p to k.
Romashka [77]

Answer:

\boxed{k = \frac{L^2 + p}{4t}}

General Formulas and Concepts:

<u>Algebra I</u>

Basic Equality Properties

  1. Multiplication Property of Equality
  2. Division Property of Equality
  3. Addition Property of Equality
  4. Subtraction Property of Equality

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify given.</em>

<em />\displaystyle L = \sqrt{4kt - p}

<u>Step 2: Solve for </u><u><em>k</em></u>
We can use equality properties to help us rewrite the equation to get <em>k</em> as our subject:

Let's first <em>square both sides</em>:

\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\\end{aligned}

Next, <em>add p to both sides</em>:

\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\\end{aligned}

Next, <em>divide 4t by both sides</em>:

\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\& \rightarrow \frac{L^2 + p}{4t} = k \\\end{aligned}

We can rewrite the new equation by swapping sides to obtain our final expression:

\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow \boxed{k = \frac{L^2 + p}{4t}}\end{aligned}

∴ we have <em>changed</em> the subject of the formula.

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Learn more about Algebra I: brainly.com/question/27698547

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Topic: Algebra I

6 0
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Does this table represent a linear equation?
olga2289 [7]
No it does not
Hope this helps
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