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Sonja [21]
2 years ago
13

Which inequality is a true statement?

Mathematics
1 answer:
irina1246 [14]2 years ago
3 0

Answer:

C and D are the right answers

Step-by-step explanation:

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Please help me I’m in finals a don’t want to fail
Misha Larkins [42]

Answer:

1, 2, 3

Step-by-step explanation:

X <= 20 means that x has to be less than OR equal to 20.

The first option is -100. That's less than 20, so this statement is true.

The second option is 10. That's also less than 20, so this statement is also true.

The third option is 20. This is equal to 20, so this is also true.

The fourth option is 21, which is greater than 20, so it's not true.

The fifth option is 45, which is greater than 20, so it's not true.

Sorry I answered so late, hope this helps even though you probably don't need it anymore.

4 0
3 years ago
Alejandro bought a new refrigerator for $856 with a 25% discount and
oksano4ka [1.4K]

Answer:

$695.94

Step-by-step explanation:

25% of 856 = 214

6.3% of 856 = 53.928

856 + 53.928 = 909.928

909.928 - 214 = 695.928 about 695.94

7 0
3 years ago
Read 2 more answers
Among all pairs of numbers whose sum is 100, find a pair whose product is as large as
miv72 [106K]

Answer:

99+1

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
If Leslie travels 1/3 of a mile in 5/6 of an hour and maintains a constant speed, what is her distance per hour?
hammer [34]
D = S × T
S = D ÷ T
T =D ÷S

sorry thats all i can do
6 0
3 years ago
Solve sin x - (3sin x-1) = 0
soldi70 [24.7K]

Answer:

\large\boxed{x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi,\ k\in\mathbb{Z}}

Step-by-step explanation:

\sin x-(3\sin x-1)=0\\\\\sin x-3\sin x+1=0\qquad\text{subtract 1 from both sides}\\\\-2\sin x=-1\qquad\text{divide both sides by 2}\\\\\sin x=\dfrac{1}{2}\Rightarrow x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi,\ k\in\mathbb{Z}

\text{Equation:}\\\\\sin x=a\\\\\text{has solutions}\\\\x=\theta+2k\pi\ \vee\ x=(\pi-\theta)+2k\pi\\\\\text{Why}\ 2k\pi?\\\text{Because the sine function has a period of}\ 2\pi.

\text{look at the table}\\\\\sin x=\dfrac{1}{2}\to x=\dfrac{\pi}{6}\ \vee\ x=\pi-\dfrac{\pi}{6}=\dfrac{5\pi}{6}

\text{Other solution:}\\\\\sin x=\dfrac{1}{2}\Rightarrow x=\sin^{-1}\dfrac{1}{2}\\\\x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi

3 0
3 years ago
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