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Tju [1.3M]
3 years ago
13

Hi pls help me thankssspls provide me with workings thankss :)​

Mathematics
1 answer:
Vinil7 [7]3 years ago
8 0

Step-by-step explanation:

(i)

Using cos(a - b) = cos a cos b + sin a sin b

\frac{4}{5} = cos a cos b + \frac{1}{5}

cos a cos b = \frac{4}{5} -\frac{1}{5} = \frac{3}{5}

(ii)

Using cos(a + b) = cos a cos b - sin a sin b

cos(a + b) = \frac{3}{5}-\frac{1}{5}=\frac{2}{5}

(iii)

Using cot a = \frac{cos a}{sin a}

=(\frac{cos A}{sin A} )(\frac{cos B}{sin B} )

=\frac{cos A cos B}{sin A sin B}

=\frac{\frac{3}{5} }{\frac{1}{5} }  =\frac{3}{5} × 5

= 3

please give me a brainliest answer

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Please help i need help geometry is very hard for me i am dumb
stiks02 [169]

Answer:

G.  ABD = 74

H.  DBC = 206

I.  XYW = 33.75

J.  WYZ = 46.25

Step-by-step explanation:

For G and H: You have a straight line (ABC) with another line coming off of it, creating two angles (ABD and DBC).  A straight line has an angle of 180 degrees.  This means that the two angles from the straight line when combined will give you 180 degrees.  Solve for x.

ABD + DBC = ABC

(1/2x + 20) + (2x - 10) = 180

1/2x + 20 + 2x - 10 = 180

5/2x + 10 = 180

5/2x = 170

x = 108

Now that you have x, you can solve for each angle.

ABD = 1/2x + 20

ABD = 1/2(108) + 20

ABD = 54 + 20

ABD = 74

DBC = 2x - 10

DBC = 2(108) - 10

DBC = 216 - 10

DBC = 206

For I and J:  For these problems, you use the same concept as before.  You have a right angle (XYZ) that has within it two other angles (XYW and WYZ).  A right angle has 90 degrees. Combine the two unknown angles and set it equal to the right angle.  Solve for x.

XYW + WYZ = XYZ

(1 1/4x - 10) + (3/4x + 20) = 90

1 1/4x - 10 + 3/4x + 20 = 90

2x + 20 = 90

2x = 70

x = 35

Plug x into the angle values and solve.

XYW = 1 1/4x - 10

XYW = 1 1/4(35) - 10

XYW = 43.75 - 10

XYW = 33.75

WYZ = 3/4x + 20

WYZ = 3/4(35) + 20

WYZ = 26.25 + 20

WYZ = 46.25

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\frac{7}{66}

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