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3 years ago

What is the value of y in the 1/4y =12

Mathematics

2 answers:

aliina [53]3 years ago

6 0

Answer:

Step-by-step explanation:

baherus [9]3 years ago

5 0

Answer:

48 would be your answer. <3

Step-by-step explanation:

1/4y=12

<em>Multiply both sides by 4.</em>

4 * (1/4y) = (4) * (12)

y=48

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Two more than the quotient of a number and 5 is 8.<br><br> use variable w for the unknown number.

KengaRu [80]

Answer:

The answer is that w = 30

Step-by-step explanation:

To find this, we start by modeling the equation.

w/5 + 2 = 8

We know it looks like this since they say quotient, which means division problem.

w/5 + 2 = 8

w/5 = 6

w = 30

7 0

3 years ago

Match the values with the statistical measures for these data points. 34,37,39,32,48,45,53,62,58,61,60,41

QveST [7]

Answer:

I do not know the full answer, But I do know this;

Maximum: 62

Minimum: 32

Step-by-step explanation:

6 0

3 years ago

a patio is the shape of a rectangle with a width of 8 feet and a length of 9 feet what is the area in square feet

sergiy2304 [10]

Area of a rectangle = length * width

Area = 9 feet * 8 feet

Area = 72 square feet

3 0

3 years ago

The range of all real numbers x such that 2x − 5 < 7 and 4x + 10 > 6 is

hammer [34]

2x - 5 < 7
2x = 12
x = 6

4x + 10 > 6
4x = - 4
x = - 1

( - 1 , 6 )

i am a mathematics teacher. if anything to ask please pm me

5 0

3 years ago

Find the length of midsegment YZ in trapezoid ABCD when A(-5,-6) B(-6,-2) C(-4,0) and D(3,2)

Luda [366]

Answer:

Option C

Step-by-step explanation:

Since, Y and Z are the midpoints of sides AB and CD of the given trapezoid.

Segment YZ will the midsegment of trapezoid ABCD.

By the theorem of midsegment,

m(YZ) = $\frac{1}{2}(AD+BC)$

By using expression for the length of a segment between two points,

Length of a segment = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance between two points A(-5, -6) and D(3, 2),

AD = $\sqrt{(3+5)^2+(2+6)^2}$

AD = $\sqrt{64+64}$

AD = $\sqrt{128}$

AD = $8\sqrt{2}$

Distance between B(-6, -2) and C(-4, 0)

BC = $\sqrt{(-6+4)^2+(-2-0)^2}$

BC = $\sqrt{8}$

BC = $2\sqrt{2}$

Therefore, m(YZ) = $\frac{1}{2}(8\sqrt{2}+2\sqrt{2})$

= $\frac{1}{2} (10\sqrt{2})$

= $5\sqrt{2}$

Option C will be the answer.

7 0

3 years ago