Find the median of each set of data 12,8,6,4,10,1 6,3,5,11,2,9,5,0 30,16,49,25

Mathematics

1 answer:

ICE Princess25 [194]4 years ago

8 0

Answer:

Step-by-step explanation:

The median is the number in the middle :)

You might be interested in

20 points!! What is the value of p? 10p+5= 18p–6/2 A–8 B–1/8 C4 D8

Artemon [7]

The answer is D.) 8

Explanation: 10p+5= 18p–6/2

Subtraction Property of equality states that you subtract the same number from both sides of an equation.

Subtract 10p from both sides of an equation

10p+5-10p = 18p-62-10p

Simplify:

5 = 8p -62

Addition Property of equality states that you add the same number from both sides of an equation.

Add 62 to both sides of an equation:

5+62 = 8p -62 +62

Simplify:

67 = 8p

Division Property of equality states that you divide the same number from both sides of an equation.

Divide by 8 in equation [3] ;

Simplify;

p = 8.375 ≈ 8 (approx)

Therefore, the value of p is, 8

Hope this helps :) sorry if wrong and sorry about confusion.

8 0

3 years ago

How can I factorise (2x cubed - 5x + 3) ?

PilotLPTM [1.2K]

$2x^3-5x+3=2x^3-2x-3x+3\\\\=2x(x^2-1)-3(x-1)\\\\=2x\underbrace{(x^2-1^2)}_{use\ (*)}-3(x-1)\ \ \ |(*)\ a^2-b^2=(a-b)(a+b)\\\\=2x\underbrace{(x-1)}_{(**)}(x+1)-3\underbrace{(x-1)}_{(**)}\\\\=(x-1)[2x(x+1)-3]\\\\=(x-1)\underbrace{(2x^2+2x-3)}_{(***)}\\\\(***)\ 2x^2+2x-3\to a=2;\ b=2;\ c=-3\\\\x=\frac{b^2\pm\sqrt{b^2-4ac}}{2a}$

$therefore\\x=\frac{-2\pm\sqrt{2^2-4(2)(-3)}}{2(2)}=\frac{-2\pm\sqrt{4+24}}{4}=\frac{-2\pm\sqrt{28}}{4}=\frac{-2\pm\sqrt{4\cdot7}}{4}=\frac{-2\pm2\sqrt7}{4}\\\\=\frac{-1\pm\sqrt7}{2}\\\\so,\ the\ answer:\\\\(x-1)\cdot2\left(x-\frac{-1-\sqrt7}{2}\right)\left(x-\frac{-1+\sqrt7}{2}\right)\\\\=\boxed{(x-1)(2x+1+\sqrt7)\left(x+\frac{1-\sqrt7}{2}\right)}=\boxed{\frac{1}{2}(x-1)(2x+1+\sqrt7)(2x+1-\sqrt7)}$

7 0

3 years ago

Read 2 more answers

Find the demand function for the marginal revenue function. Recall that if no items are sold, the revenue is 0.

Pepsi [2]

The integral that is needed to solve the demand function is R(x) = 599x - 0.14 $x^{3/2}$

<h3>What is Demand Function?</h3>

A demand function describes the mathematical relationship between the quantity demanded and one or more determinants of the demand, as the price of the good or service, the price of complementary and substitute goods, disposable income, etc.

Here, given differential equation;

R'(x) = 599 - 0.21 $\sqrt{x}$