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VARVARA [1.3K]
2 years ago
8

I will give Brainliest Simplify. 1/4(16a – 46) – (2a – 6)

Mathematics
2 answers:
BigorU [14]2 years ago
3 0

Answer:

2a+ −11/2

Step-by-step explanation:

<em><u>Let's simplify step-by-step.</u></em>

1/4 (16a − 46) − (2a − 6)

<em>Distribute the Negative Sign:</em>

= 1/4 (16a − 46) + −1 (2a − 6)

= 1/4 (16a − 46) + −1 (2a) + (−1) (−6)

= 1/4 (16a − 46) + −2a + 6

<em>Distribute:</em>

= (1/4) (16a) + (1/4) (−46) + −2a + 6

=4a + −23/2 + −2a + 6

<em>Combine Like Terms:</em>

= 4a + −23/2 + −2a + 6

= (4a + −2a) + (−23/2 + 6)

= 2a + −11/2

<em>Answer:</em>

=2a + −11/2

hope this helps. p.s. i really need brainliest :)

bezimeni [28]2 years ago
3 0

Answer:

2a - 5.5

Step-by-step explanation:

1/4(16a - 46) - (2a - 6)

<em>Use the distributive property to multiply 1/4 by 16a−46.</em>

1/4 * 16a + 1/4(-46) - (2a - 6)

4a - 11.5 - (2a - 6)

<em>To find the opposite of 2a - 6, find the opposite of each term.</em>

4a - 11.5 - 2a -(-6)

4a - 11.5 - 2a + 6

<em>Combine 4a and -2a to get 2a.</em>

2a - 11.5 + 6

<em>Add 6 to -11.5 to get -5.5</em>

2a - 5.5

1/4(16a - 46) - (2a - 6) simplified is 2a - 5.5.

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In ⊙O, ST and VT are tangents. m∠STV = 22°. Find the value of a, b, and m∠SOV.
Rasek [7]

Answer:

\huge \orange {\boxed {a =202\degree}}

\huge \purple {\boxed { b = 158\degree}}

\huge \red {\boxed {m\angle SOV = 158\degree}}

Step-by-step explanation:

In \odot O, ST and VT are tangents at points S and V respectively.

\therefore OS\perp ST, \:and\: OV\perp VT

\therefore m\angle OST=m\angle OVT = 90\degree

In quadrilateral OSTV,

m\angle SOV +m\angle OST+m\angle OVT+m\angle STV = 360\degree

(By interior angle sum postulate of a quadrilateral)

m\angle SOV +90\degree +90\degree +22\degree  = 360\degree

m\angle SOV +202\degree  = 360\degree

m\angle SOV = 360\degree-202\degree

\huge \red {\boxed {m\angle SOV = 158\degree}}

\because b = m\angle SOV

(Measure of minor arc is equal to measure of its corresponding central angle)

\huge \purple {\boxed {\therefore b = 158\degree}}

\because a + b= 360\degree

(By arc sum property of a circle)

\therefore a = 360\degree - b

\therefore a = 360\degree -158\degree

\huge \orange {\boxed {\therefore a =202\degree}}

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