The hypothesis is given as
H0: μd< 0
H1: μd > 0
<h3>How to solve for the hypothesis.</h3>
The null hypothesis is given as
H0: μd< 0
<h3>The alternative hypothesis is given as </h3>
H1: μd > 0
SWe have to find the value of s
we would use this formula s = sqrt [ (Σ(di - d)^2 / (n - 1) ]
This gives us 3.454
Next we have to determine the standard error
s / √(n)
3.454/2.8284
= 1.22
Degree of freedom = 8 - 1
= 7
t = (x1 - x2) - D / S.E
= 1.025
Find t critical at 0.10
= 1.895
P-value = 0.1697
d. Given that p value is greater thatn 0.1 we fail to reject the null hypothesis.
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Answer:
NO
Step-by-step explanation:
The left side 0.25 does not equal to the right side 0.125 , which means that the given statement is false.
923 rounded to the nearest hundred is 900. If the number was over 950 it would be 1,000 but since it was below is closer or nearest to 900
1/9
Find the common denominator, 1/3 can be multiplied to get to ninths. 1/3 is equivalent to 3/9, and so 4/9 minus 3/9 is 1/9.
