I believe the answer is 5040
First, we need to get the slope of the equation of the train tracks. We can transform the given equation into the slope-intercept form.
4x +2y = 16
y = -2x +8
The slope of the equation is -2.
A perpendicular line will have the same slope but the opposite sign.
So, the slope of the line of the train crossing is 2. Since, it will pass through the point (8,15), the slope-intercept form can also be used to solve for the equation.
y = mx + b
The slope is 2, so m=2. We solve b by substituting the coordinates.
15 = 2(8) +b
b = -11
The equation is now,
y = -2x - 11
Or it can also be expresses as:
2x - y = 11
It is d y-1x2-Bc+29 I say that bc it says that in the answer up above
Degree is the value of the highest power of the variable, and hence in this case is 8
