Determine the missing angle.

An architect is designing a building.each floor will be 12 feet tall.

Kamila [148]

Answer:

There are four students working on a project in math class. Miguel has completed 1/8 of the project, Gina has completed 13% of the project, Jatziry has completed 0.10 of the project, and Keva has completed 1/9 of the project. Make a list of the students in order from least to greatest by the amount of the project they have completed.

Step-by-step explanation:

I don't have points

3 0

3 years ago

Which expression is modeled by this set of arrows on the number line

diamong [38]

Answer:

A

Step-by-step explanation:

they are both -

8 0

3 years ago

Read 2 more answers

Without solving, NO SOLUTION describes which equation?

CaHeK987 [17]

Answer:

The equation 'y = y + 1' represents NO SOLUTION.

Hence, option 'C' is true.

Step-by-step explanation:

a)

6a = 9a

subtract 9a from both sides

6a - 9a = 9a - 9a

-3a = 0

divide both sides by -3

-3a / -3 = 0/-3

Simplify

a = 0

b)

5x = 28

divide both sides by 5

5x/5 = 28/5

x = 28/5

c)

y = y + 1

subtract y from both sides

y - y = y+1-y

0 = 1

These sides are not equal, so

NO SOLUTION!

d)

y + 5 = 12

subtract 5 from both sides

y + 5 - 5 = 12 - 5

y = 7

Conclusion:

Therefore, the equation 'y = y + 1' represents NO SOLUTION.

Hence, option 'C' is true.

5 0

3 years ago

Read 2 more answers

How do I solve this.....I'm really dumb

Margaret [11]

Answer: 40 suit size

6.9 time

2 & 5 in runs scored

Step-by-step explanation:

mode is really easy. All you have to do is calculate which number appears the most

7 0

3 years ago

The graph h = −16t^2 + 25t + 5 models the height and time of a ball that was thrown off of a building where h is the height in f

Thepotemich [5.8K]

Answer:

part 1) 0.78 seconds

part 2) 1.74 seconds

Step-by-step explanation:

step 1

At about what time did the ball reach the maximum?

Let

h ----> the height of a ball in feet

t ---> the time in seconds

we have

$h(t)=-16t^{2}+25t+5$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

so

The x-coordinate of the vertex represent the time when the ball reach the maximum

Find the vertex

Convert the equation in vertex form

Factor -16

$h(t)=-16(t^{2}-\frac{25}{16}t)+5$

Complete the square

$h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+5+\frac{625}{64}$

$h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}\\h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}$

Rewrite as perfect squares

$h(t)=-16(t-\frac{25}{32})^{2}+\frac{945}{64}$

The vertex is the point $(\frac{25}{32},\frac{945}{64})$

therefore

The time when the ball reach the maximum is 25/32 sec or 0.78 sec

step 2

At about what time did the ball reach the minimum?

we know that

The ball reach the minimum when the the ball reach the ground (h=0)

For h=0

$0=-16(t-\frac{25}{32})^{2}+\frac{945}{64}$

$16(t-\frac{25}{32})^{2}=\frac{945}{64}$

$(t-\frac{25}{32})^{2}=\frac{945}{1,024}$

square root both sides

$(t-\frac{25}{32})=\pm\frac{\sqrt{945}}{32}$

$t=\pm\frac{\sqrt{945}}{32}+\frac{25}{32}$

the positive value is

$t=\frac{\sqrt{945}}{32}+\frac{25}{32}=1.74\ sec$

8 0

3 years ago