Answer:
1
Step-by-step explanation:
What is the largest of 3 consecutive integers such that the sum of the first and third is equal to three times the second?
3 consecutive angles
= x, x + 1, x + 2
We are told in the question that:
the sum of the first and third is equal to three times the second
a + c = 3b
x + x + 2 = 3(x + 1)
2x + 2 = 3x + 3
3x - 2x = 2 - 3
x = -1
The largest of the three numbers is the third number
= x + 2
x = -1
x + 2 = -1 + 2
The third and largest number is 1
Answer:
20% I think this is the answer
Step-by-step explanation:
Assuming that you mean "simplified form", we have to cancel every common divisor of both numerator and denumerator.
36 is factored as 
34 is factored as 
So, the two numbers only have a factor 2 in common, meaning that the simplified form of this fraction is
Answer:
9(m+H) = a
Step-by-step explanation:
m=a/9-H
The first step is to add H to each side.
m+H = a/9 -H+H
m+H = a/9
Now multiply both side by 9
9(m+H) = a/9*9
9(m+H) = a
