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Tema [17]
3 years ago
5

Three drivers competed in the same fifteen drag races. The mean and standard deviation for the race times of each of the drivers

are given.
- Driver A had a mean race time of 4.01 seconds and a standard deviation of 0.05 seconds.

- Driver B had a mean race time of 3.96 seconds and a standard deviation of 0.12 seconds.

- Driver C had a mean race time of 3.99 seconds and a standard deviation of 0.19 seconds.


Which driver do you predict will win the next drag race? Support your prediction using the mean and standard deviation.
Mathematics
1 answer:
Monica [59]3 years ago
8 0

Answer:

Driver B

Step-by-step explanation:

From the given options, Driver B will win the next race because the previous result shows that Driver B has the fastest race time due to the fact that it recorded the lowest mean race time.

Similarly, the standard deviation of 0.12 seconds illustrates that the driver keep-up with the bearest minimum time frame all through the entire race time.

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Answer:

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A psychological experiment was conducted to investigate the length of time (time delay) between the administration of a stimulus
aleksklad [387]

Answer:

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject H_0: \mu= 1.6, we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

The significance level for this test is 0.05.

Step-by-step explanation:

In this case, we want to prove if there is significant evidence that the mean differs from 1.6 seconds. That is the same as having evidence to reject the the hypothesis H_0:\mu= 1.6 (the null hypothesis always have the equal sign).

We have to test the null hypothesis

H_0:\mu= 1.6

The significance level for this test is 0.05

Calculation of the t-statistic:

t=\frac{M-\mu}{s/\sqrt{n}} =\frac{2.2-1.6}{0.57/\sqrt{36}} =\frac{0.6}{0.063}= 9.47

If we look up in a t-table for t=9.47 and df=(36-1)=35, we get this value appears with a probability of zero. A large number like that is very unlikely to happen.

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject H_0: \mu= 1.6, we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

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How long is the base of a parallelogram if it has an area of 100 m2 and a height of 5 m?
DochEvi [55]
   
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Answer: 55.20$

Step-by-step explanation:

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2. Multiply 120(the cost without any discount/tax) with the new discount percentage

3. Now with the answer from multiplying subtract it from 120.

4. With the answer, multiply the tax percentage(0.08)

5. Now add It to the discounted price.

6. Round it to the nearest hundredth

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2 years ago
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Try this option:
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