Question 1)
Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x
F(G(x)) = 3(2x - 3)^2 + 1
F(G(x)) =3(4x^2 - 12x + 9) + 1
F(G(x)) = 12x^2 - 36x + 27 + 1
F(G(x)) =12x^2 - 36x + 28
Question 2)
Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x
H -1 (x) = x (inverse)
Agreed, I had to take a test on it and y did equal 70
Answer:
y = 1/5x - 7/5
Step-by-step explanation:
y = 1/5x + b
-1 = 1/5(2) + b
-1 = 2/5 + b
-7/5 = b
Given
A rectangular park of length 60 m breadth 50 m encloses with volleyball court of length 18 m and breadth 10 m.
To find:
The area of the park excluding the court at the rate of Rs 110 per square meter.
Solution:
Area of a rectangle is:

Area of whole park is:


Area of volleyball court is:


Now, the area of the park excluding the court is:



Therefore, the area of the park excluding the court is 2820 square meter.