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Arada [10]
3 years ago
11

Of the relations graphed below, three are functions and one is not.

Mathematics
1 answer:
tresset_1 [31]3 years ago
6 0

Answer:

vertical line

Step-by-step explanation:

If it is possible to draw any vertical line (a line of constant x) which crosses the graph of the relation more than once, then the relation is not a function.

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f(0) =  ( f(k) +f(-k) ) / 2

f(0) = (16 - 4) / 2

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f(0) = 6  → ANSWER

*Remember that f(0) = m(0) + n = n

If we have f(x) = mx + n, then:

f(k)= mk + n     and       f(-k)= -mk + n

If we add them:

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= mk + n -mk + n

= 2n

= 2f(0)

So we conclude that:

f(0) = [f(k) + f(-k)] / 2

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3 years ago
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Answer:

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Step-by-step explanation:

Hope it is helpful......

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Step-by-step explanation:

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Step-by-step explanation:

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