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ANEK [815]
3 years ago
9

Question 11 (1 point) (02.05 LC) What number is 60% of 80? Input only whole numbers.

Mathematics
1 answer:
sweet [91]3 years ago
5 0

Answer:

48

Step-by-step explanation:

60% of 80 is 48

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WORTH 15 POINTSSSSSSSSS
QveST [7]

Answer:

15

Step-by-step explanation:

Difference in distances = 75-60 = 15 miles

So Car A travels 15 miles more than Car A in an hour

Answered by Gauthmath

4 0
3 years ago
Luke and Matthew ran a lemonade stand on Saturday.
SOVA2 [1]

Answer:

15$

Step-by-step explanation:

Okey so first we establish that 25 is 100%

Matthew gets 60%

First we find 10% by dividing both sides by 10

2.5 = 10%

Then we times these numbers by 6 to find 60%

<u>60%  = 15</u>

Matthew will earn <u>15$</u>

Luke will earn 10$

4 0
4 years ago
Read 2 more answers
Under average driving conditions, the life lengths of automobile tires of a certain brand are found to follow an exponential dis
wariber [46]

Answer:

a) P(X>30000)=1-( 1- e^{-\frac{30000}{30000}})=e^{-1}=0.368

b) P(X>30000|X>15000)=P(X>15000)=1-( 1- e^{-\frac{15000}{30000}})=e^{-0.5}=0.607

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}, x>0

And 0 for other case. Let X the random variable that represent "life lengths of automobile tires of a certain brand" and we know that the distribution is given by:

X \sim Exp(\lambda=\frac{1}{30000})

The cumulative distribution function is given by:

F(X) = 1- e^{-\frac{x}{\mu}}

Part a

We want to find this probability:

P(X>30000) and for this case we can use the cumulative distribution function to find it like this:

P(X>30000)=1-( 1- e^{-\frac{30000}{30000}})=e^{-1}=0.368

Part b

For this case w want to find this probability

P(X>30000|X>15000)

We have an important property on the exponential distribution called "Memoryless" property and says this:

P(X>a+t| X>t)=P(X>a)  

On this case if we use this property we have this:P(X>30000|X>15000)=P(X>15000+15000|X>15000)=P(X>15000)

We can use the definition of the density function and find this probability:

P(X>15000)=1-( 1- e^{-\frac{15000}{30000}})=e^{-0.5}=0.607

7 0
3 years ago
Can you please give a step by step answer with the reasons?<br> Thank you
ivann1987 [24]
Yhtgrfexrgyhujjiedwzwct
8 0
3 years ago
If f(x)= 1/x+2 and a&gt;3, which of the following could be f(a)
Xelga [282]
I think it’s D not sure
5 0
3 years ago
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