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RoseWind [281]
3 years ago
9

I NEED ANSWER ASAP WILL MARK BRAINLY Which term is defined as the change in the direction of light when it goes from one medium

into a different medium?
transmission

reflection

absorbtion

refraction
Physics
2 answers:
pickupchik [31]3 years ago
8 0

Answer:

reflection

Explanation:

katovenus [111]3 years ago
8 0

Answer:

Refraction

I think

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A mxiture of n2 and H2 has mole fraction of 0.4 and 0.6 respectively. Determine the density of the mixture at one bar and 0 c.
SOVA2 [1]

Answer:

The density of the mixture is 0.55kg/m^3

Explanation:

P = 1bar = 100kN/m^2, T = 0°C = 273K, n = 0.4+0.6 = 1mole

PV = nRT

V = nRT/P = 1×8.314×273/100 = 22.70m^3

Mass of N2 = 0.4×28 = 11.2kg

Mass of H2 = 0.6×2 = 1.2kg

Mass of mixture = 11.2 + 1.2 = 12.4kg

Density of mixture = mass/volume = 12.4/22.7 = 0.55kg/m^3

3 0
4 years ago
Give an example of how energy from the sun gets into your cells
bulgar [2K]
We eat plants that use the energy from the sun to make food
6 0
3 years ago
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An object with a mass of 1.5 kg accelerates 10.0 m/s^2? when an unknown force is applied to it. What is the amount of the force?
Shkiper50 [21]

Answer:

15 N

Explanation:

f=ma

f=1.5*10

f=15 N

5 0
3 years ago
A centrifugal pump is operating at a flow rate of 1 m3/s and a head of 20 m. If the specific weight of water is 9800 N/m3 and th
tamaranim1 [39]

Answer:

<em>The power required by the pump is nearly 230.588 kW</em>

Explanation:

Flow rate of the pump Q = 1 m^3/s

the head flow H = 20 m

specific weight of water γ = 9800 N/m^3

efficiency of the pump η = 85%

First note that specific gravity of water is the product of the density of water and acceleration due to gravity.

γ = ρg

where ρ is density. For water its value is 1000 kg/m^3

g is the acceleration due to gravity = 9.81 m/s^2

The power to lift this water at this rate will be gotten from the equation

P = ρgQH

but ρg = γ

therefore,

P = γQH

imputing values, we'll have

P = 9800 x 1 x 20 = 196000 W

But the centrifugal pump that will be used will only be able to lift this amount of water after the efficiency factor has been considered. The power of pump needed must be greater than this power.

we can say that

196000 W is 85% of the power of the pump power needed, therefore

196000 = 85% of P_{p}

where P_{p} is the power of the pump needed

85% = 0.85

196000 = 0.85P_{p}

P_{p} = 196000/0.85 = 230588.24 W

<em>Pump power = 230.588 kW</em>

3 0
3 years ago
Tĩnh lực tĩnh điện [lực cu lông] giữa 2 điện tích điểm q1,q2 biết q1=2.10-9 q2=4.10-9 r=3cm
Anettt [7]
  • q1=2×10^{-9}C
  • q2=4×10^{-9}C
  • Radius=3cm=0.3m

Using coulmb's law

\\ \bull\tt\dashrightarrow F=k\dfrac{q1q2}{r^2}

\\ \bull\tt\dashrightarrow F=8.98\dfrac{2\times 10^{-9}\times 4\times 10^{-9}}{(0.3)^2}

\\ \bull\tt\dashrightarrow F=8.98\dfrac{8\times 10^{-18}C^2}{0.09m^2}

\\ \bull\tt\dashrightarrow F=\dfrac{71.84\times 10^{-18}C^2}{0.09m^2}

\\ \bull\tt\dashrightarrow F=798.2\times 10^{18}Nm^2/C^2

\\ \bull\tt\dashrightarrow F=7.9\times 10^{16}Nm^2/C^2

6 0
3 years ago
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