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sineoko [7]
3 years ago
14

Two friends are playing a version of proton golf where the hole is marked by a single proton. The first friend reads his meter,

and declares he has a field strength of 24.0 N/C. The second friend looks at her meter and realizes she is three times as far away. What field strength does the second friend's meter read?
Physics
1 answer:
yarga [219]3 years ago
5 0

Answer:

the electric field strength on the second one is 2.67 N/C.

Explanation:

the electric fiel on the first one is:

E1 = k×q/(r^2)

r^2 = k×q/(E1)

     = (9×10^9)×(q)/(24.0)

     = 375000000q

then the electric field on the second one is:

E2 = k×q/(R^2)

we know that R = 3r

                       R^2 = 9×r^2

E2 = k×q/(9×r^2)

     = k×q/(9×375000000q)

     = k/(9×375000000)

     = (9×10^9)/(9×375000000)

     = 2.67 N/C

Therefore, the electric field strength on the second one is 2.67 N/C.

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