Two friends are playing a version of proton golf where the hole is marked by a single proton. The first friend reads his meter,
1 answer:
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Answer:
<em>The fifth option is the correct answer: mv; 2 mv</em>
Explanation:
<u>Change of Momentum</u>
Assume an object has a momentum p1 and after some interaction it now has a momentum p2, the change of momentum is
The momentum is computed as
Where m is the mass of the object and v its speed. Now let's analyze the situation of both the ball and the clay.
The clay has an initial speed v and a mass m, thus its initial momentum is
When it hits the wall, it sticks, thus its final speed is 0 and
The change of momentum is
The absolute change is mv
Now for the ball, the initial condition is the same as it was for the clay, but the ball hits back at the same speed, thus its final momentum is
The change of momentum is
The absolute change is 2mv
The fifth option is the correct answer: mv; 2 mv
1. 12.75 J
Assuming that the force applied is parallel to the ramp, so it is parallel to the displacement of the cart, the work done by the force is
where
F = 15 N is the magnitude of the force
d = 85 cm = 0.85 m is the displacement of the cart
Substituting in the formula, we get
2. 10.6 N
In this part, the cart reaches the same vertical height as in part A. This means that the same work has been done (because the work done is equal to the gain in gravitational potential energy of the object: but if the vertical height reached is the same, then the gain in gravitational potential energy is the same, so the work done must be the same).
Therefore, the work done is
However, in this case the displacement is
d = 120 cm = 1.20 m
Therefore, the magnitude of the force in this case is
Answer:
The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field.
The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current.
The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines.
Explanation:
The magnitude of the magnetic force exerted on a current-carrying wire due to a magnetic field is given by
(1)
where I is the current, L the length of the wire, B the strength of the magnetic field, the angle between the direction of the field and the direction of the current.
Also, B, I and F in the formula are all perpendicular to each other. (2)
According to eq.(1), we see that the statement:
<em>"The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines.</em>"
is correct, because when the current is perpendicular to the magnetic field, and the force is maximum.
Moreover, according to (2), we also see that the statements
<em>"The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field. "</em>
<em>"The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current. "</em>
because F (the force) is perpendicular to both the magnetic field and the current.