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Neporo4naja [7]
3 years ago
8

M is the midpoint of AD. What value of x will make triangles ABM and DCM congruent?

Mathematics
2 answers:
Sophie [7]3 years ago
6 0
The answer is 7. 

the Brainliest please!!
Nesterboy [21]3 years ago
4 0

Answer: x=7


Step-by-step explanation: In the given figure M is a midpoint .By definition of midpoint AM=MD.It is given AB=CD in figure. Two of the sides are equal .to prove the triangles to be congruent by SSS the third side must be equal

That is BM=CM,

Or  4x-1=3x+6

Subtracting 3x both sides

4x-3x-1=3x-3x+6

x-1=6.

Adding 1 both sides

x=7.

x=7 will make the third side equal and hence the triangles will be congruent by SSS.


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3 years ago
The numbers​ 1, 2,​ 3, 4, and 5 are written on slips of​ paper, and 2 slips are drawn at random one at a time without replacemen
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<h2>Answer:</h2>

(a)

The probability is :  1/2

(b)

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<h2>Step-by-step explanation:</h2>

The numbers​ 1, 2,​ 3, 4, and 5 are written on slips of​ paper, and 2 slips are drawn at random one at a time without replacement.

The total combinations that are possible are:

(1,2)   (1,3)    (1,4)    (1,5)

(2,1)   (2,3)   (2,4)   (2,5)

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(5,1)   (5,2)   (5,3)   (5,4)

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Let A denote the event that the first number is 4.

and B denote the event that the sum is: 9.

Let P denote the probability of an event.

We are asked to find:

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We know that it could be calculated by using the formula:

P(A|B)=\dfrac{P(A\bigcap B)}{P(B)}

Hence, based on the data we have:

P(A\bigcap B)=\dfrac{1}{20}

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P(B)=\dfrac{2}{20}

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Hence, we have:

P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}

(b)

Let A denote the event that the first number is 3.

and B denote the event that the sum is: 8.

Let P denote the probability of an event.

We are asked to find:

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Hence, based on the data we have:

P(A\bigcap B)=\dfrac{1}{20}

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P(B)=\dfrac{2}{20}

( since, there are just two outcomes such that the sum is: 8

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Hence, we have:

P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}

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