Since you know the area and the width, you can divide the area by the width to find the length. This gives you a length of 110 yards. To find the perimeter of the soccer field, you would add all the side lengths together. Since the width is 70, you would add 70 + 70, along with the length, 110 + 110. This gives you a perimeter of 360.
Answer:
see the explanation
Step-by-step explanation:
we have
closed circle on 2 to closed circle on 6
That means -----> All real numbers greater than or equal to 2 and less than or equal to 6
In interval notation is ------> [2,6]
In set builder notation is ----> { x ∈ R | x ≥ 2 and x ≤ 6 }
Answer:
Step-by-step explanation:
ok. you said 2000 and 2500 so I'll just solve for both.
this is very simple, mis/mia wants to earn 2000/2500 so let's solve
this can be done two ways. an equation way, or a dividing way. I personally like the dividing way.
2000 divided by 55= 36.36-- so she will have to tune up 37 bicycles
2500 divided by 55= 45.45-- so she will have to tune 46 bicycles. this is because 46 bicycles, times the amount of money == just a little over 2500 so she has reached her goal
Hello!
Here are some rules to determine the number of significant figures.
- Numbers that are not zero are significant (45 - all are sigfigs)
- Zeros between non-zero digits are significant (3006 → all are sigfigs)
- Trailing zeros are not significant (0.067 → the first two zeros are not sigfigs)
- Trailing zeros after a decimal point are always significant (1.000 → all are sigfigs)
- Trailing zeros in a whole number are not significant (7800 → the last two zeros are not sigfigs)
- In scientific notation, the exponential digits are not significant, known as place holders (6.02 x 10² → 10² is not a sigfig)
Now, let's find the number of significant figures in each given number.
A). 296.54
Since these digits are all <em>non-zero</em>, there are 5 significant figures.
B). 5003.1
Since the two <em>zeros are between non-zero digits</em>, they are significant figures. Thus, there are 5 significant figures.
C). 360.01
Again, the two zeros are between non-zero digits. There are 5 significant figures.
D). 18.3
All of these digits are non-zero, hence, there are 3 significant figures.
Therefore, expression D has the fewest number of significant figures being 3.
Answer:
Yes because a taller person would have a higher chance of getting the ball in the net
Step-by-step explanation:
