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Alex777 [14]
3 years ago
9

A geologist was looking at a new

Chemistry
1 answer:
Arte-miy333 [17]3 years ago
6 0

Answer:

D. Volume

Explanation:

Properties mentioned in the question;

colour = gray

Nonmetallic

Density = 3.8 g/mL

Volume = 48.3 mL

Of the mentioned, which is extensive ?

Extensive properties are those properties that are proportional to the amount of substance present.

The correct option is D. Volume. The other properties do not change with increasing or decreasing amount of the mineral

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She did no work while she posed because she did not move the torch or the book.

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names the process which takes place when a red litmus paper turns white when dropped into chlorine water​
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Answer. Explanation: Chlorine gas bleaches the damp litmus (red or blue). Bleaching is an oxidation process.

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A 50.0 mL sample of 1.54×10−2 M NaSO4 is added to 50.0 mL of 1.28×10−2 Ca(NO3)2. What percentage of the Ca2+ remains unprecipita
Gwar [14]
The reaction would be as shown below;
Na2SO4 + Ca(NO3)2 = CaSO4 + 2 NaNO3
The moles of NaSO4 will be;
   = 0.05 × 0.0154 = 0.00077 moles
While the number of moles of Ca(NO3)2
   = 0.05 × 0.0128 = 0.00064 moles
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3 years ago
When 189.6 g of ethylene (C2H4) burns in oxygen to give carbon dioxide and water, how many grams of CO2 are formed?
Andreyy89

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6.76 g

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3 years ago
A sample of brass is put into a calorimeter (see sketch at right) that contains of water. The brass sample starts off at and the
Ierofanga [76]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The specific heat is  c_b  = 0.402 J / g \cdot ^oC

Explanation:

From the question we are told that

    The mass of  the sample is  m = 54.4 \ g

     The mass of the water is  m_w = 150.0 \ g

     The initial temperature of the sample is  T_i  = 95.1 ^oC

     The initial temperature of the water is  T_{w_i} =  15^oC

     The final temperature of the water is  T  =  17.6 ^oC

Note the final temperature of water is equal to the final temperature of brass sample

    The pressure is  P =1 \ atm

Generally for according to the law of energy conservation

    The heat lost by sample  =  The heat gain by water

   

The heat lost by brass sample is  mathematically evaluated as    

          H_L  =  m * c_b  *  [T_i - T]

Where c_b is the specific neat of the brass sample

The heat gained  by water is  mathematically evaluated as          

        H_g  = m_w *c_w * [T_w - T ]

where c_w is the specific heat of water which has a constant value of  

     c_w =  4.186  joule/gram

So

    H_L  =  H_g \ \equiv m* c_b  * [T_i -T] =  m_w * c_w * [T - T_w]

substituting values

    52.4 * c_b  * [95.1  - 17.6] =  150 * 4.186 * [ 17.6 - 15.0]

    c_b  = 0.402 J / g \cdot ^oC

4 0
4 years ago
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