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3 years ago

Which statement best describes how photosynthesis follows the law of conservation of mass?

Chemistry

1 answer:

leva [86]3 years ago

8 0

Answer:

O The number of oxygen atoms in the reactants used by this process equals the total number of oxygen atoms in the products.

Explanation:

The statement that best describes how photosynthesis follows the law of conservation of mass is that the number of oxygen atoms in the reactants used by this process is equal to the total number of oxygen atoms in the products.

The equation of photosynthesis reaction is given as:

6CO₂ + 6H₂O → C₆ H₁₂ O₆ + 6O₂

According to the law of conservation of mass, matter is neither created nor destroyed during the course of a chemical reaction.

By the virtue of this, the number of oxygen atom on both sides of the expression must be the same. Also, the number of carbon and hydrogen atoms must also be the same.

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Look up the density of the material the object is made of in kg/m³.

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3 years ago

Describe how a compound different from the elements that make it up?

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D. A salt e.g NaCl is held by ionic bond

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3 years ago

What fraction of the space within the atom is occupied by the nucleus?

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Explanation:

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3 years ago

Solutions of sodium carbonate and silver nitrate react to form solid silver carbonate and a solution of sodium nitrate. A soluti

ella [17]

Answer :

The mass of excess mass of $Na_2CO_3$ , $AgNO_3,Ag_2CO_3\text{ and }NaNO_3$ are, 1.908 g, 0 g, 12.144 g and 3.74 g respectively.

Explanation : Given,

Mass of $Na_2CO_3$ = 4.25 g

Mass of $AgNO_3$ = 7.50 g

Molar mass of $Na_2CO_3$ = 106 g/mole

Molar mass of $AgNO_3$ = 170 g/mole

Molar mass of $Ag_2CO_3$ = 276 g/mole

Molar mass of $NaNO_3$ = 85 g/mole

First we have to calculate the moles of $Na_2CO_3$ and $AgNO_3$ .

$\text{Moles of }Na_2CO_3=\frac{\text{Mass of }Na_2CO_3}{\text{Molar mass of }Na_2CO_3}=\frac{4.25g}{106g/mole}=0.040moles$

$\text{Moles of }AgNO_3=\frac{\text{Mass of }AgNO_3}{\text{Molar mass of }AgNO_3}=\frac{7.50g}{170g/mole}=0.044moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$Na_2CO_3+2AgNO_3\rightarrow Ag_2CO_3+2NaNO_3$

From the balanced reaction we conclude that

As, 2 moles of $AgNO_3$ react with 1 mole of $Na_2CO_3$

So, 0.044 moles of $AgNO_3$ react with $\frac{0.044}{2}=0.022$ moles of $Na_2CO_3$

From this we conclude that, $Na_2CO_3$ is an excess reagent because the given moles are greater than the required moles and $AgNO_3$ is a limiting reagent and it limits the formation of product.

The excess mole of $Na_2CO_3$ = 0.040 - 0.022 = 0.018 mole

Now we have to calculate the mass of excess mole of $Na_2CO_3$ .

$\text{Mass of }Na_2CO_3=\text{Moles of }Na_2CO_3\times \text{Molar mass of }Na_2CO_3=(0.018mole)\times (106g/mole)=1.908g$