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pav-90 [236]
3 years ago
13

3S8 + 8 OH- + 8 S3 + 4 HOOH

Chemistry
1 answer:
NemiM [27]3 years ago
4 0

Answer:

Second order

Explanation:

We could obtain the order of reaction by looking at the table very closely.

Now notice that in experiment 1 and 2, the concentration of [OH^-] was held constant while the concentration of [S8] was varied.  So we have;

a situation in which the rate of reaction was tripled;

0.3/0.1 = 2.10/0.699

3^1 = 3^1

Therefore the order of reaction with respect to  [S8] is 1.

For [OH^-], we have to look at experiment 2 and 3 where the concentration of [S8] was held constant;

x/0.01 = 4.19/2.10

x/0.01 = 2

x = 2 * 0.01

x = 0.02

So we have;

0.02/0.01 = 2^1

2^1 = 2^1

The order of reaction with respect to  [OH^-] = 1

So we have the overall rate law as;

Rate = k[S8]^1  [OH^-] ^1

Overall order of reaction = 1 + 1 = 2

Therefore the reaction is second order.

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matrenka [14]

Answer:

0.263M of CH₃COOH is the concentration of the solution.

Explanation:

The reaction of acetic acid (CH₃COOH) with NaOH is:

CH₃COOH + NaOH → CH₃COO⁻Na⁺ + H₂O

<em>1 mole of acetic acid reacts per mole of NaOH to produce sodium acetate and water.</em>

<em />

In the equivalence point, moles of acetic acid are equal to moles of NaOH and moles of NaOH are:

0.0375L × (0.175 moles / L) = 6.56x10⁻³ moles of NaOH = moles of CH₃COOH.

As the sample of acetic acid had a volume of 25.0mL = 0.025L:

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<em>0.263M of CH₃COOH is the concentration of the solution</em>

3 0
3 years ago
Identifying Processes of the Carbon Cycle
Mademuasel [1]

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yKpoI14uk [10]
Well,  STP means standard temperature and pressure

In this condition, it is safe to assume that the moles of specie given will be equal to the moles of specie sought

I think the volume of the Carbon dioxide that it produced will also be 3.75 liters

Hope this helps
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