The first three terms of the sequence defined by the recursive formula are 2, -7/2 and -3/2
Given:

where,
n = number of terms
First term, a1 = 2
Second term, a2

a2 = {(2 - 1)/ 4} - 2
= 1/4 - 2
= (1-8) / 4
= - 7/4
Third term, a3
= {(3-1) / 4} - 2
= 2/4 - 2
= 1/2 - 2
= (1-4) / 2
= -3/2
Therefore, the first three terms of the sequence defined by the recursive formula are 2, -7/2 and -3/2
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g(x)=2(x-4)(x+3)
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b = 14
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Since both angles are diagonal each other, they are equal to each other.
5b = b + 56
-b -b (subtract b from both sides)
<u>4b</u> = <u>56</u>
4 4 (divide both sides by 4 to solve for b)
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