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DanielleElmas [232]
2 years ago
15

Will mark brainliest

Mathematics
1 answer:
SVETLANKA909090 [29]2 years ago
3 0

Answer:

I think the answer should be Mat A cause it has more space.

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Triangle P Q R is shown. Angle Q R P is a right angle. Angle R P Q is 30 degrees and angle P Q R is 60 degrees. Given right tria
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Answer:

The correct option is option (c).

Sin \ P= \frac {RQ}{PQ}

Step-by-step explanation:

Right angled triangle:

  • One angle must be 90° and other two angles are acute angle.
  • The hypotenuses is the longest side of the triangle and opposite right angle.
  • It follows the Pythagorean Theorem.

Given that,

∠QRP= 90°, ∠RPQ= 30°, ∠PQR = 60°

we know that,

sin \theta =\frac{Opposite }{Hypotenuse}

for sin P , the opposite is QR.

The hypotenuse is PQ.

Therefore,

Sin \ P= \frac {RQ}{PQ}

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Step-by-step explanation:

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A map of an airport is laid out in a coordinate plane. An aeroplane starts at a gate at (0, 0.1). To reach a runway, the plane t
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Take the numbers and divide them i believe

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Complete the table below.
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Answer:

4 , 2, 8, 4 ..............

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Thirty elves would like to build a skating ring so they can all use it at the same time. Santa tells them, they need at least 40
Delicious77 [7]

Answer:

The Possible dimension of the ring could be;

20 ft × 60 ft

25 ft × 48 ft

30 ft × 40 ft

60 ft × 20 ft

48 ft × 25 ft

40 ft × 30 ft

Step-by-step explanation:

Given:

Number of skaters = 30

Area for each skater = 40 sq ft

We need to find the dimension of rectangular ring the are going to build.

Now we know that they building the skating ring such that they all can use at same time.

Hence if the all use at same time then we will find the total area first.

Total area can be calculated by multiplying Number of skaters with area required for each skaters.

Framing the equation we get;

Total area = 30\times 40 = 1200 \ ft^2

Hence The total area of the rectangular ring would be 1200 sq. ft.

Now we know that Total area is equal to product of length and width.

length\times width =1200ft^2

1200 can be written as = 20 × 60, 25 × 48, 30 × 40,60 × 20,48 × 25,40 × 30

Hence the Possible dimension of the ring could be;

20 ft × 60 ft

25 ft × 48 ft

30 ft × 40 ft

60 ft × 20 ft

48 ft × 25 ft

40 ft × 30 ft

3 0
3 years ago
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