<u>27 = 6x + 4y </u>= 1 7/20 = 3 4/5<u>
</u>20 = 2x + 5y<u>
</u>
Answer:
bottom left :)
Step-by-step explanation:
Answer:
B.
R (2,4)
soln
center(h,k)=(6,1)
radius (r)=5units
so
eqn of circle is (x-6)^2+(y-1)^2=5^2
2 2
or, 25=x +y -12x-2y+36+1 now , only the given point (6,1)satisfies the eqn so this point lies on circle
hello,
Jack wants to know how many families in his small neighborhood of 60 homes would help organize a neighborhood fund-raising party. He put all the addresses in a bag and drew a random sample of 30 addresses. He then asked those families if they would help organize the fund-raising party. He found that 12% of the families would help organize the party. He claims that 12% of the neighborhood families would be expected to help organize the party. Is this a valid inference?
Yes, this is a valid inference because the 30 families speak for the whole neighborhood
it's the correct one because if he ask 30 families so they talk to their neighborhood so its will be 60 ;) so its correct,
hope this help
Answer:
Part one: The function rule for the area of the rectangle is A(x) = 3x² - 2x
Part two: The area of the rectangle is 8 feet² when its width is 2 feet
Step-by-step explanation:
Assume that the width of the rectangle is x
∵ The width of the rectangle = x feet
∵ The length of the rectangle is 2 ft less than three times its width
→ That means multiply the width by 3, then subtract 2 from the product
∴ The length of the rectangle = 3(x) - 2
∴ The length of the rectangle = (3x - 2) feet
∵ The area of the rectangle = length × width
∴ A(x) = (3x - 2) × x
→ Multiply each term in the bracket by x
∵ A(x) = x(3x) - x(2)
∴ A(x) = 3x² - 2x
∴ The function rule for the area of the rectangle is A(x) = 3x² - 2x
∵ The rectangle has a width of 2 ft
∵ The width = x
∴ x = 2
→ Substitute x by 2 in A(x)
∵ A(2) = 3(2)² - 2(2)
∴ A(2) = 3(4) - 4
∴ A(2) = 12 - 4
∴ A(2) = 8
∴ The area of the rectangle is 8 feet² when its width is 2 feet
