Answer:
Intervals = (1,064) , (1,036)
Step-by-step explanation:
Given:
Use 95% method
Mean = 1,050
Standard deviation = 7
Find:
Intervals.
Computation:
95% method.
⇒ Intervals = Mean ± 2(Standard deviation)
⇒ Intervals = 1,050 ± 2(7)
⇒Intervals = 1,050 ± 14
⇒ Intervals = (1,050 + 14) , (1,050 - 14)
⇒ Intervals = (1,064) , (1,036)
Each of the small pitcher will contain 4 cups of water while each of the large pitcher will contain 16 cups of water.
Therefore, two equal-sized large pitchers will hold 32 cups of water while the two equal-sized small pitchers will hold 8 cups of water
<h3>
Larger Pitchers</h3>
The 2 larger pitchers are equal in size.
Let
each size of the large pitcher = x
Two large size pitcher = 2x
<h3>
Smaller Pitchers</h3>
The 2 smaller pitchers are equal in size
let
each size of the pitcher = y
Two small sized pitchers = 2y
<h3>Pitchers Capacities</h3>
The whole pitchers holds 40 cups of water. Therefore,
The capacity of one large pitcher minus the capacity of one small pitcher is 12 cups. Therefore,
Combine the equations.
2x + 2y = 40
x - y = 12
x + y = 20
2y = 8
y = 8 / 2
y = 4
x - 4 = 12
x = 12 + 4
x = 16
learn more on geometry here: brainly.com/question/26109140?referrer=searchResults
Answer:
B. step I think
Step-by-step explanation:
Let a = 693, b = 567 and c = 441
Now first we will find HCF of 693 and 567 by using Euclid’s division algorithm as under
693 = 567 x 1 + 126
567 = 126 x 4 + 63
126 = 63 x 2 + 0
Hence, HCF of 693 and 567 is 63
Now we will find HCF of third number i.e., 441 with 63 So by Euclid’s division alogorithm for 441 and 63
441 = 63 x 7+0
=> HCF of 441 and 63 is 63.
Hence, HCF of 441, 567 and 693 is 63.
Answer:
y = 8
Step-by-step explanation:
Step 1: Write out equation
13 + 3y = 37
Step 2: Subtract 13 on both sides
3y = 24
Step 3: Divide both sides by 3
y = 8
