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2 years ago

If aslam sold a book in Rs.118 and he got 50% profit,then the cost price of the book was?

Mathematics

1 answer:

pashok25 [27]2 years ago

4 0

Answer: CP = Rs 78.667

Step-by-step explanation:

The data given to us are

Selling price = Rs. 118

Profit percentage = 50

Now using the form formula

CP = ( SP * 100 ) / ( 100 + percentage profit).

Where;

Cp is cost price and Sp is selling price

So we input our numbers

CP = ( 118 × 100 ) / ( 100 + 50)

CP = 11800 / 150

CP = Rs 78.667

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X – 6y - 9 = 0 x = 8y + 6 What is a resulting equation?

serious [3.7K]

Answer:

-2y + 3 = 0

Step-by-step explanation:

x - 6y - 9 = 0

-6y - 9 = -x subtract x from both sides

6y + 9 = x divide both sides by -1

x = 8y + 6

6y + 9 = 8y + 6 replace x with 6y + 9

-2y + 9 = 6 subtract 8y from both sides

-2y + 3 = 0 subtract 6 from both sides

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2 years ago

(7x2) x 3

Sindrei [870]

First you need to multiply the one in the bracket 7x2 which is 14 then u must multiply it with 3 to get the answer so 14x3 which equals to 42

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10 months ago

Use cylindrical coordinates. find the volume of the solid that lies within both the cylinder x2 y2 = 9 and the sphere x2 y2 z2 =

marissa [1.9K]

In Cartesian coordinates, the region is given by $-3\le x\le3$ , $-\sqrt{9-x^2}\le y\le\sqrt{9-x^2}$ , and $-\sqrt{16-x^2-y^2}\le z\le\sqrt{16-x^2-y^2}$ . Converting to cylindrical coordinates, using

$\begin{cases}\mathbf x(r,\theta,\zeta)=r\cos\theta\\\mathbf y(r,\theta,\zeta)=r\sin\theta\\\mathbf z(r,\theta,\zeta)=\zeta\end{cases}$

we get a Jacobian determinant of $r$ , and the region is given in cylindrical coordinates by $0\le\theta\le2\pi$ , $0\le r\le3$ , and $-\sqrt{16-r^2}\le z\le\sqrt{16-r^2}$ .

The volume is then

$\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=3}\int_{z=-\sqrt{16-r^2}}^{z=\sqrt{16-r^2}}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=\dfrac{4(64-7\sqrt7)\pi}3$

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2 years ago

#2 and please provide explaination !

quester [9]

Answer:

Total overripe fruit = 48

Step-by-step explanation:

Step 1: Assume the value of oranges

Let oranges be x

Oranges = x

Apples = 32 + x

Overripe oranges = 3/5 of oranges

= 3x/5

Overripe apples = 1/3 of apples

= 1/3 (32 + x)

Step 2: Find x (oranges)

Number of overripe apples and number or overripe oranges are equal.

3x/5 = 1/3 (32 + x)

3 (3x) = 5(32 + x)

9x = 160 + 5x

4x = 160

x = 40

Step 3: Find the total number of overripe fruit.

Total overripe fruit = Overripe apples + Overripe oranges

Total overripe fruit = 1/3 (32 + x) + 3x/5

Total overripe fruit = 1/3 (32 + 40) + 3(40)/5

Total overripe fruit = 24 + 24

Total overripe fruit = 48

4 0

2 years ago

On a coordinate plane, parallelogram A B C D has points (3, 6), (6, 5), (5, 1), and (2, 2).

jeka94

Answer:

13 square units

Step-by-step explanation:

The bounding rectangle is 4 units wide and 5 units high, so has an area of 4×5 = 20 square units. From that are subtracted the areas of 4 triangles. 2 of them are 3 wide and 1 high, so have a combined area of 3×1 = 3 square units. The other two are 1 wide and 4 high, so have a combined area of 1×4 = 4 square units.

Then the area of the parallelogram is ...

20 -3 -4 = 13 . . . . square units

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3 years ago