Please look at photo

How do I solve these questions? <br> 5(1+9v)<br> 20b+12<br> -9/4r=-9/2

MatroZZZ [7]

5(1+9v) = 5+ 45v
20b+12= 4(5b+3)
And the last one is r=2
Hope this helps!

7 0

3 years ago

The cost to rent a bicycle is $5.00 plus $3.00 per hour for x hours. What equation

Rainbow [258]

Answer:

3

Step-by-step explanation:

hope this helps with the problem

8 0

3 years ago

Read 2 more answers

HELPPPPP MEEEEEE Which one is not a solution to y = 3x - 5? A. (0, –5) B. (– 1, – 2) C. (5/3, 0) D. (2, 1)

nignag [31]

Answer:

Step-by-step explanation:

Let's examine the individual things

A. x=0 --> y=3.0-5=-5 True

B. x=-1 --> y=3.(-1)-5=-8 False

C. x=5/3 -->y=3(5/3)-5=0 True

D. x=2 --> y=3.2-5=1 True

Answer is B.

You don't understand, you can ask me :)

7 0

2 years ago

Genetic Defects Data indicate that a particular genetic defect occurs in of every children. The records of a medical clinic show

Dovator [93]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The probability that there exist 60 or more defected children is $P(x \ge 60)=0.0901$

Looking at the value for this probability we see that it is not so small to the point that the observation of this kind would be a rare occurrence

Step-by-step explanation:

From the question we are told that

in every 1000 children a particular genetic defect occurs to 1

The number of sample selected is $n= 50,000$

The probability of observing the defect is mathematically evaluated as

$p = \frac{1}{1000}$

$= 0.001$

The probability of not observing the defect is mathematically evaluated as

$q = 1-p$

$= 1-0.001$

$= 0.999$

The mean of this probability is mathematically represented as

$\mu = np$

Substituting values

$\mu = 50000*0.001$

$= 50$

The standard deviation of this probability is mathematically represented as

$\sigma = \sqrt{npq}$

Substituting values

$= \sqrt{50000 * 0.001 * 0.999}$

$= \sqrt{49.95}$

$= 7.07$

the probability of detecting $x \ge60$ defects can be represented in as normal distribution like

$P(x \ge 60)$

in standardizing the normal distribution the normal area used to approximate $P(x \ge 60)$ is the right of 59.5 instead of 60 because x= 60 is part of the observation

The z -score is obtained mathematically as

$z = \frac{x-\mu }{\sigma }$

$= \frac{59.5 - 50 }{7.07}$

$=1.34$

The area to the left of z = 1.35 on the standardized normal distribution curve is 0.9099 obtained from the z-table shown z value to the left of the standardized normal curve

Note: We are looking for the area to the right i.e 60 or more

The total area under the curve is 1

So

$P(x \ge 60) \approx P(z > 1.34)$

$= 1-P(z \le 1.34)$

$=1-0.9099$

$=0.0901$

3 0

2 years ago

Henry wants to paint the ceilings and the walls of his living room. One gallon of paint covers 450 ft squared. The rooms is 24 f

Mamont248 [21]

If you would like to know how many gallons of paint will Henry need to paint his living room, you can calculate this using the following steps:

the ceiling: 24 ft * 18 ft = 432 ft squared
walls: 2 * 24 ft * 9 ft + 2 * 18 ft * 9 ft = 2 * 24 * 9 + 2 * 18 * 9 = 432 + 324 = 756 ft squared

432 ft squared + 756 ft squared = 1188 ft squared

1 gallon of paint ... 450 ft squared
x gallons of paint = ? ... 1188 ft squared

1 * 1188 = 450 * x
1188 = 450 * x /450
x = 1188 / 450
x = 2.64 gallons of paint

The correct result would be 2.64 gallons of paint.

6 0

3 years ago