For this case, the first thing we should do is use the following equation:
f (x) = 200 (1.03) ^ x
We substitute f (x) = 300:
300 = 200 (1.03) ^ x
We clear the value of x:
log1.03 (300/200) = log1.03 ((1.03) ^ x)
x = log1.03 (300/200)
x = 13.72
Answer:
the population will first reach 300 in about 13.72 years.
.333333.........% i cant write the little mark above it but it goes on continuosly.
Given:250 sheep in a 40-acre pasture.Number of sheep grazing in each acre.
250/40 = 6.25 or 6 sheep per acre
n = 6sample proportion: signified by ρSample 1: 4 → 4/6 = 0.67Sample 2: 1 → 1/6 = 0.17Sample 3: 9 → 9/6 = 1.50
multiply the sample proportion by 1-ρSample 1: 0.67(1-0.67) = 0.67(0.33) = 0.2211Sample 2: 0.17(1-0.17) = 0.17(0.83) = 0.1411Sample 3: 1.50(1-1.5) = 1.5(-0.5) = -0.75
divide the result by n. n = 6Sample 1: 0.2211/6 = 0.03685Sample 2: 0.1411/6 = 0.02352Sample 3: -0.75/6 = -0.125
square root of the quotient to get the standard error.Sample 1: √0.03685 = 0.1919Sample 2: √0.02352 = 0.1534Sample 3: √-0.125 = invalid
z value 95% confidence 1.96.
Sample 1: 1.96 * 0.1919 = 0.3761 or 37.61% margin of errorSample 2: 1.96 * 0.1534 = 0.3007 or 30.07% margin of error
