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2 years ago

I am having trouble finding this out will anyone help?

Mathematics

1 answer:

dalvyx [7]2 years ago

5 0

Answer: g = 4

Step-by-step explanation:

30 = 26+g

4 = g

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Brainliest if correct

lyudmila [28]

Answer:

1. (-4)^2 = 16

2. (-3)^3 = -27

Step-by-step explanation:

8 0

1 year ago

Which of the following are quadratic functions A. Y =5x-3/2+x^2 B. Y=x^2+5x-2 C. Y=-x+2 D. Y=x-1/x

Svetllana [295]

Answer:

A and B

Step-by-step explanation:

Quadratic Equations: f(x) = a(bx - h)² + k

Quadratic equations always have a degree of 2. That means that we will always have an x² term. Of the 4 choices, only A and B offer a term of x², making them a quadratic.

8 0

3 years ago

Read 2 more answers

Solve the system of equations:x + 3y - z = -4 2x - y + 2z = 13 3x - 2y - z = -9

tatiyna

Answer:

The solution to the system of equations is

$\begin{gathered} x=\frac{179}{13} \\ \\ y=-\frac{279}{39} \\ \\ z=-\frac{48}{13} \end{gathered}$

Explanation:

Giving the system of equations:

$\begin{gathered} x+3y-z=-4\ldots\ldots\ldots\ldots\ldots\ldots..........\ldots\ldots\ldots\ldots.\ldots\text{.}\mathrm{}(1) \\ 2x-y+2z=13\ldots\ldots...\ldots\ldots\ldots\ldots..\ldots..\ldots\ldots\ldots\ldots\ldots.(2) \\ 3x-2y-z=-9\ldots\ldots\ldots.\ldots\ldots\ldots\ldots....\ldots\ldots.\ldots\ldots\ldots\text{.}\mathrm{}(3) \end{gathered}$

To solve this, we need to first of all eliminate one variable from any two of the equations.

Subtracting (2) from twice of (1), we have:

$5y-4z=-21\ldots\ldots\ldots\ldots\ldots.\ldots.\ldots..\ldots..\ldots\ldots.\ldots..\ldots\text{...}\mathrm{}(4)$

Subtracting (3) from 3 times (1), we have

$3y-5z=-3\ldots\ldots...\ldots\ldots..\ldots\ldots\ldots\ldots\ldots.\ldots\ldots\ldots\ldots\ldots..\ldots\ldots(5)$

From (4) and (5), we can solve for y and z.

Subtract 5 times (5) from 3 times (4)

$\begin{gathered} 13z=-48 \\ \\ z=-\frac{48}{13} \end{gathered}$

Using the value of z obtained in (5), we have

$\begin{gathered} 3y-5(-\frac{48}{13})=-3 \\ \\ 3y+\frac{240}{13}=-3 \\ \\ 3y=-3-\frac{240}{13} \\ \\ 3y=-\frac{279}{13} \\ \\ y=-\frac{279}{39} \end{gathered}$

Using the values obtained for y and z in (1), we have

$\begin{gathered} x+3(-\frac{279}{39})-(-\frac{48}{13})=-4 \\ \\ x-\frac{279}{13}+\frac{48}{13}=-4 \\ \\ x-\frac{231}{13}=-4 \\ \\ x=-4+\frac{231}{13} \\ \\ x=\frac{179}{13} \end{gathered}$

8 0

1 year ago

Ain. 1.5 ft. 0.5 it. What is the surface area of the figure in square inches help

Aleonysh [2.5K]

Answer:

17.5 ft.²

Step-by-step explanation:

Surface area: 2(4 x 0.5) + 2(4 x 1.5) + 2(0.5 x 1.5)
=> 2(2) + 2(6) + 2(0.75)
=> 4 + 12 + 1.5
=> 17.5 ft.²

Conclusion:

Therefore, the surface area is 17.5 ft.².

Hoped this helped.

$GeniusUser$

3 0

2 years ago

Read 2 more answers

Write an expression in simplest form for the perimeter of each figure

Juli2301 [7.4K]

QUESTION 12

The given figure has five unequal sides.

The perimeter is the distance around the figure.

So we add all the lengths of the sides of the rectangle to get,

$Perimeter = 5x + 4x + 2.8y + 2x + 2.2y$

We regroup the like terms to obtain,

$Perimeter = 5x + 4x +2x + 2.8y + 2.2y$

This will simplify to give us,

$Perimeter = 11x + 5.0y$

$Perimeter = 11x + 5y$

QUESTION 13

The given figure has two pairs of sides that are equal in length and three unequal sides.

The perimeter can be found by adding all the lengths of the sides of the of the figure.

This will give us

$Perimeter = 6b + 5a + 3b + 4 + 3a + 2b + 5a$

We regroup like terms to obtain,

$Perimeter = 6b + 2b+ + 3b + 5a + 5a +3a + 4 +$

This finally simplifies to ,

.
$Perimeter = 11b + 13a + 4 +$

QUESTION 14

This plane figure has four sides that are equal to 4j and two sides that are equal to 2h.

We add all the lengths of the sides of the plane figure to get,

$Perimeter =4j + 4j+ 4j+ 4j + 2h + 2h$

This will simplify to give us,

$Perimeter =16j + 4h$

6 0

2 years ago