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Oksi-84 [34.3K]
3 years ago
15

Enter a recursive rule for the geometric sequence. 6, −18, 54, −162, ...

Mathematics
1 answer:
svlad2 [7]3 years ago
5 0

Answer:

The required recursive formula is:

a_n=(-3)\times a_{n-1}

Step-by-step explanation:

We are given a geometric sequence as:

6,-18,54,-162,.....

Clearly after looking at different terms of the sequence we could observe that the sequence is an geometric progression (G.P.) with common ratio= -3 denoted by r.

Let a_n represents the nth term of the sequence.

This means that:

a_1=6, a_2=-18, a_3=54, a_4=-162,......

As the common ratio is -3.

so,

a_1=6\\\\a_2=-18=(-3)\times a_1\\\\a_3=54=(-3)\times a_2\\\\.\\.\\.\\.\\.\\.\\.\\.\\.a_n=(-3)\times a_{n-1}

Hence, the required recursive formula for the geometric sequence is:

a_n=(-3)\times a_{n-1}

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one number is equal to the square of another. find the numbers if both are positive and their sum is 1122
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Answer:

One number is 561

The other number is 23.6854

Step-by-step explanation:

x = y^2                One number = the square of another

x + y^2 = 1122     The sum of the two numbers is 1122

Substitute y^2 in for x on the second equation.

y^2 + y^2 = 1122    Combine like terms on the left

2y^2 = 1122            Divide by 2

y^2 = 1122/2

y^2 = 561                Take the square root of both sides.

y = 23.6854            

x = y^2

x = 561

y^2 = 561


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