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Alenkinab [10]
3 years ago
6

Which of the following correctly simplifies the expression ?

Mathematics
2 answers:
gavmur [86]3 years ago
8 0

Answer:

4) 81/16

Step-by-step explanation:

Just solve the equation,

{3^2.5^0/4}^2

(9×1/4)^2

(81/16)

Hope it helps!

Leni [432]3 years ago
3 0

Answer:

4

Step-by-step explanation:

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DerKrebs [107]
1 meter = 39.370 inches.....so 5 meters = (5)(39.370) = 196.85 inches
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3 years ago
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What is u = kx + ух, for x
Ivahew [28]

Answer:

<h2>x=  \frac{u}{k + y}</h2>

Step-by-step explanation:

u = kx + ух

First of all factorize x out at the right side of the equation

That's

u = x(k + y)

Divide both sides by ( k + y) to make x stand alone

That's

<h3>\frac{x(k + y)}{k + y}  =  \frac{u}{k + y}</h3>

We have the final answer as

<h3>x =  \frac{u}{k + y}</h3>

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Helllllppppp please????
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Answer:

7.75

Step-by-step explanation:

(I'm assuming you need to find the missing side of the triangle)

To find missing values in a right angle. we will use the pythagoras theorem which states that:

h^2 = a^2 + b^2

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Answer from Gauthmath

8 0
3 years ago
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Tell if each is an arithmetic sequence. If it is, give the common difference.
taurus [48]

Answers:

5.) Yes it is, you add each one to itself to get the next number

6.) Yes, you subtract 5 from each number

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5 0
2 years ago
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chubhunter [2.5K]

Answer:


Step-by-step explanation:

Statements                          Reasons

----------------------------------------------------------------

1. ∠V ≅ ∠Y                        Given

2. WZ bisects ∠VWY          Given

3. ∠VWZ ≅ ∠YWZ            Definition of Angle Bisector (2)

4. WZ ≅ WZ                         Reflexive Property

5. ΔVWZ ≅ ΔYWZ               AAS Theorem (1,3,4)

**In case you didn't know the definitions**

Angle Bisector - A line, segment or ray that divides an angle into two congruent angles

Reflexive Property - X = X

AAS Postulate -  If two angles and a non-included side of one triangle are congruent to the corresponding parts of another triangle, then the triangle's are congruent

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