Mr, Obrien needs to buy 8 television for the school. Each television costs $795. Mr. O'Brien has 120 fifty-dollar bills that he
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Answer:
Confidence Interval: (21596,46428)
Step-by-step explanation:
We are given the following data set:
10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929
Formula:
where are data points,
is the mean and n is the number of observations.
Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821
Confidence interval:
Putting the values, we get,