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Studentka2010 [4]

3 years ago

11

Can someone please help me find mDE i will give good rating

1 answer:

Ray Of Light [21]3 years ago

8 0

Answer:

548.522077317

Sorry if this is wrong I don't know a lot about circle arcs

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Solve for x. 5 1/2 ≥ 1.6x<br> x ≥3 7/16<br> x ≤ 3 7/16<br> x ≥ 8 4/5<br> x ≤ 8 4/5

11Alexandr11 [23.1K]

Answer:

x < 3 7/16

Step-by-step explanation:

8 0

3 years ago

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A company needs to replace 27 out of 45 desks in their office. What percent of the desks need to be replaced?

sleet_krkn [62]

60%

Solve by creating a proportion
27/45 = x/100

Cross multiply to get 2700=45x

Divide 45 on both sides to get x=60

6 0

3 years ago

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Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.

prohojiy [21]

Answer:

$2.25$

Step-by-step explanation:

$(6x^{-2})^2(0.5x)^4\\\\=(6^2(x^{-2})^{2})(0.5^4x^4)\ \ \ \ \ \ \ \ \ \ \ \ \ as\ (ab)^m=a^mb^m\\\\=36\times 0.5^4((x^{-2})^2x^4)\ \ \ \ \ \ \ \ \ \ as\ multiplication\ is\ associative\ a(bc)=(ab)c\\\\=36\times 0.0625(x^{-4}x^4)\ \ \ \ \ \ \ \ \ \ \ as\ (x^m)^n=x^{mn}\\\\=(36\times 0.0625)(x^{-4+4})\ \ \ \ \ \ \ \ \ \ \ as\ x^mx^n=x^{m+n}\\\\=2.25x^0\\\\=2.25\ \ \ \ \ \ \ \ \ \ \ \ as\ x^0=1\\\\(6x^{-2})^2(0.5x)^4=2.25$

7 0

3 years ago

The length of a rectangle is shown below:

ludmilkaskok [199]

Answer:

C(5,-4), D(-4,-4)

Have a great day :)

Step-by-step explanation:

7 0

3 years ago

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Please help me on this it a about to be due

makvit [3.9K]

Answer:

A

Step-by-step explanation:

sin is opposite/hypotenuse, which is 24/26, simplifying to 12/13

8 0

3 years ago

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