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Gelneren [198K]
3 years ago
12

Find the measure of

Mathematics
2 answers:
AVprozaik [17]3 years ago
7 0

Answer:

55

Step-by-step explanation:

since b is 110, you will have to divide 110 by 2 to find out the answer of c because its a half of b and that leaves you with 55, also a is 55 two

c=55

a=55

d=30

Nezavi [6.7K]3 years ago
7 0

Answer:

∠C = 110°

Step-by-step explanation:

the figure is a kite so a line from B to D would bisect those angles and for a triangle that contains a total of 180°.

180° - 1/2(110° + 30°) = 180° - 1/2(140°) = 180° - 70° = 110°

You might be interested in
Solve the inequality and graph the solution<br> 4x-5&gt;7
ohaa [14]

Answer:

x > 3

interval notation: (3, ∞)

Step-by-step explanation:

Given the inequality statement: 4x - 5 > 7,

The goal is to isolate x and find its solution.

Start by adding 5 to both sides:

4x - 5 + 5 > 7 + 5

4x > 12

Divide both sides by 4:

4x/4 > 12/4

x > 3

The solution can also be expressed in the following interval notation:

(3, ∞).

In terms of graphing, it involves an empty circle on the endpoint, x = 3, as it is not included as a solution. The solution to the given inequality statement must be greater than 3.  

5 0
3 years ago
Help please multiply matrix D by matrix E.
aleksandr82 [10.1K]
It's going to be a 3x2. Im assuming its [ 5 10 on the first row, second row would be -2, -4, then the bottom row would be 1, 2] Hope I helped!

3 0
3 years ago
Read 2 more answers
Find the area of the figure.
Hoochie [10]

Answer:

384 cm

Step-by-step explanation:

7.5 x 24 = 180

8.5 + 7.5 = 16

16 x 24 = 384

5 0
3 years ago
Find an equation of the plane orthogonal to the line
jolli1 [7]

The given line is orthogonal to the plane you want to find, so the tangent vector of this line can be used as the normal vector for the plane.

The tangent vector for the line is

d/d<em>t</em> (⟨0, 9, 6⟩ + ⟨7, -7, -6⟩<em>t </em>) = ⟨7, -7, -6⟩

Then the plane that passes through the origin with this as its normal vector has equation

⟨<em>x</em>, <em>y</em>, <em>z</em>⟩ • ⟨7, -7, -6⟩ = 0

We want the plane to pass through the point (9, 6, 0), so we just translate every vector pointing to the plane itself by adding ⟨9, 6, 0⟩,

(⟨<em>x</em>, <em>y</em>, <em>z</em>⟩ - ⟨9, 6, 0⟩) • ⟨7, -7, -6⟩ = 0

Simplifying this expression and writing it standard form gives

⟨<em>x</em> - 9, <em>y</em> - 6, <em>z</em>⟩ • ⟨7, -7, -6⟩ = 0

7 (<em>x</em> - 9) - 7 (<em>y</em> - 6) - 6<em>z</em> = 0

7<em>x</em> - 63 - 7<em>y</em> + 42 - 6<em>z</em> = 0

7<em>x</em> - 7<em>y</em> - 6<em>z</em> = 21

so that

<em>a</em> = 7, <em>b</em> = -7, <em>c</em> = -6, and <em>d</em> = 21

4 0
3 years ago
Solve and check please help ty
raketka [301]

so wt's the question of this pic?

5 0
3 years ago
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