Let width = w
Let length = l
Let area = A
3w+2l=1200
2l=1200-3w
l=1200-3/2
A=w*l
A=w*(1200-3w)/2
A=600w-(3/2)*w^2
If I set A=0 to find the roots, the maximum will be at wmax=-b/2a which is exactly 1/2 way between the roots-(3/2)*w^2+600w=0
-b=-600
2a=-3
-b/2a=-600/-3
-600/-3=200
w=200
And, since 3w+2l=1200
3*200+2l=1200
2l = 600
l = 300
The dimensions of the largest enclosure willbe when width = 200 ft and length = 300 ft
check answer:
3w+2l=1200
3*200+2*300=1200
600+600=1200
1200=1200
and A=w*l
A=200*300
A=60000 ft2
To see if this is max area change w and l slightly but still make 3w+2l=1200 true, like
w=200.1
l=299.85
A=299.85*200.1
A=59999.985
Dividing of cells a sample problems of geometric
progression. Given that the intial number of cells is 40, then it will double
every 20 minutes. Within 7 hours the cells will divide into w by 21 times. So the
number of cells after 7 hrs is 4,194,040 cells.
Answer:
what do you need help with?
The formula is
V (t)=V0 (1-r)^t
V (t)?
V0 1000
R 0.05
T 5 years
V (5)=1,000×(1−0.05)^(5)=773.78
