Answer:
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Use compound interest formula F=P(1+i)^n twice, one for each deposit and sum the two results.
For the P=$40,000 deposit,
i=10%/2=5% (semi-annual)
number of periods (6 months), n = 6*2 = 12
Future value (at end of year 6),
F = P(1+i)^n = 40,000(1+0.05)^12 = $71834.253
For the P=20000, deposited at the START of the fourth year, which is the same as the end of the third year.
i=5% (semi-annual
n=2*(6-3), n = 6
Future value (at end of year 6)
F=P(1+i)^n = 20000(1+0.05)^6 = 26801.913
Total amount after 6 years
= 71834.253 + 26801.913
=98636.17 (to the nearest cent.)
Answer:
I think it could be D
Step-by-step explanation:
Because if you move point K up a little they will be congruent , I’m not 100% sure tho
There is no single solution but there is a group of solutions also known as the interval.
This can be written with an interval.
Hope this helps.
r3t40
1. Distribute the 4 with (2x-5)
2. Then add 15 to -20
3. Isolate x by adding 5 to the other side of the equal sign
4. Finally divide by 8 on both sides
