Answer:
105 g
Explanation:
We are given that
Impulse=I=1 N-s
Initial velocity,u=-3.8 m/s
Final velocity,v=5.7 m/s
We have to find the mass of the ball.
Impulse=Change in momentum
I=m(v-u)
Using the formula
Where 1 kg=1000 g
E = sigma/2 * epselon naught
E = 300 * 10^-9/(2 * 8.854 * 10^-12)
E = 1.7 * 10^4 N/C
Assuming that the electric field is uniform all across the surface:
Then, Electric flux = E * A
Electrix flux = 1.7 * 10^4 * 15 = 2.5 x 10^5 Nm^2/C
It should be b)
Answer
a) Using dimensional analysis we cannot derive the relation, But we can check the correctness of the formula.
now, L H S
s = distance
dimension of distance = [M⁰L¹T⁰]
now, equation on the right hand side
R H S
u = speed
u = m/s
Dimension of speed = [M⁰L¹T⁻¹]
dimension of time
t = sec
Dimension of time = [M⁰L⁰T¹]
Dimension of 'ut' = [M⁰L¹T⁻¹][M⁰L⁰T¹]
= [M⁰L¹T⁰]
now, acceleration= a
a = m /s²
dimension of acceleration = [M⁰L¹T⁻²]
dimension of (at²) = [M⁰L¹T⁻²][M⁰L⁰T¹][M⁰L⁰T¹]
= [M⁰L¹T⁰]
hence, the dimension are balanced.
so, L H S = R H S
b) Moment of inertia of hollow sphere =
Moment of inertia of solid sphere =
we know,
Torque is the force that causes rotation
If the same amount of torque is applied to both spheres the sphere with bigger moment of inertia would have smaller angular velocity.
Thus the solid sphere would accelerate more.
Explanation:
It is given that,
The position of a particle is given by :
(a) Velocity of a particle is given by :
Putting values,
The acceleration of the particle is given by :
(b) At t = 0,
Velocity, v = 6k m/s
Acceleration, a = 6i m/s²
velocity of object just before hitting the ground = 10 m/s
10 m/sExplanation:
here's the solution : -
=》mechanical energy is always constant, when the object is at the top of the building , the object has potential energy but no kinetic energy,
so, at the top of the building the mechanical energy = potential energy = 100 J
but at when it is dropped from the building, the whole potential energy get converted into kinetic energy, just before reaching the bottom .
so, mechanical energy in the object just before hitting the ground = kinetic energy
( potential energy = 0 )
So, kinetic energy = 100 J
now, we know
=》
( since, mass = 2 kg )
=》
=》
=》
so, velocity of object just before hitting the ground = 10 m/s