Displacement equals (velocity times time) + 1/2 *(acceleration * time squared). =. (10*4) + 1/2 * (2*2^2) = 56 meters
Answer:
Hi Iris this is Cadence I think its the Y
Explanation:
Dilly bar iris whats upp
Explanation:
Given that,
Two particles, an electron and a proton, are initially at rest in a uniform electric field of magnitude 570 N/C.
We need to find their speeds after 47.6 ns.
For electron,
The electric force is given by :
Let a be the acceleration of the electron. So,
F = ma
m is mass of electron
Let v be the final velocity of the electron. So,
v = u +at
u = 0 (at rest)
So,
For proton,
Acceleration,
Now final velocity of the proton is given by :
Hence, this is the required solution.
The final velocity of the rocket is 77.5 m/s in the direction of motion
Explanation:
The given in the problem is:
1. The rocket travels 600 m
2. It starts from rest
3. It is being accelerated uniformly at rate 5 m/s²
We need to find the final velocity
We can use this rule to solve the problem
→ v² = u² + 2 a s
where v is the final velocity, u is the initial velocity, s is the distance
and a is the acceleration
→ u = 0 m/s , a = 5 m/s² , s = 600 m
Substitute these values in the rule above
→ v² = (0)² + 2 (5)(600)
→ v² = 6000
Take √ for both sides
→ v = 77.5 m/s in the direction of motion
The final velocity of the rocket is 77.5 m/s in the direction of motion
Learn more:
You can learn more about the change in velocity in brainly.com/question/12639288
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Answer:
1) The angle of deflection will be less than 45° ( C )
2) The angle of deflection will be greater than 45° but less than 90° ( E )
Explanation:
1) Assuming that the force applied has a direction which is perpendicular to the Earth's magnetic field
∴ Fearth > Fapplied hence the angle of deflection will be < 45°
2) when the Fearth < Fapplied
the angle of deflection will be : > 45° but < 90°