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kvv77 [185]
3 years ago
15

A ball rolls off a table and it traveling with a horizontal velocity of 2 m/s and 1 point

Physics
2 answers:
morpeh [17]3 years ago
4 0

Answer:

The velocity when the ball hits the ground is obtained using v2. 2 = v1. 2 + 2 g Dy with v1=0 and Dy=h. Thus solving for v2 yields 17.1 m/s v2 = 2 g h =.

21 pages·330 KB

astra-53 [7]3 years ago
4 0

Answer:

I e jofh ndoj eohe nc n very nic e

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Answer:

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b) The height of the hill is given by:

y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2}

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Hence, the height of the hill is:

y_{0} = \frac{1}{2}gt^{2} = \frac{1}{2}9.81 m/s^{2}*(2.67 s)^{2} = 35.0 m  

I hope it helps you!

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