A ball rolls off a table and it traveling with a horizontal velocity of 2 m/s and 1 point
2 answers:
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The magnitude of the vector C is 96.32m
<h3>How to solve for the magnitude of vector c</h3>
Ax = AcosθA
= 40 cOS 20
= 37.59
Ay = AsinθA
-40sin20
= -13.68
Bx = B cos θ B
= 75Cos50
= 48.21
By = BsinθB
= 75sin50
= 57.45
Cx = AX + Bx
= 37.59 + 48.21
= 85.8
Cy = Ay + By
= -13.65 + 57.45
= 43.77
The magnitude is solved by
|c| =
= √85.8² + 43.77²
= 96.32m
The magnitude of the vector c is 96.32m
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Answer:
The taken is
Explanation:
Frm the question we are told that
The speed of car A is
The speed of car B is
The distance of car B from A is
The acceleration of car A is
For A to overtake B
The distance traveled by car B = The distance traveled by car A - 300m
Now the this distance traveled by car B before it is overtaken by A is
Where is the time taken by car B
Now this can also be represented as using equation of motion as
Now substituting values
Equating the both d
substituting values
Solving this using quadratic formula we have that